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19 Sep 2019, 21:25
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
35% (01:31) correct
65%
(01:37)
wrong
based on 88
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If \((3k)^x = 1\), what is the value of k ?
(1) k > 0
(2) x is a positive integer
What does k equal if \((3k)^x=1\)?
(1) \(k>0\)
(2) x is a positive integer
(1) \(k>0\)
(2) x is a positive integer
Updated on: 21 Sep 2019, 01:42
Originally posted by madgmat2019 on 19 Sep 2019, 21:36.
Last edited by madgmat2019 on 21 Sep 2019, 01:42, edited 1 time in total.
Last edited by madgmat2019 on 21 Sep 2019, 01:42, edited 1 time in total.
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if x not equal to 0 then k should be 1/3,-1/3 depends on x - odd/even
if x = 0 then k can be any value
(1) no use OF KNOWING ABOUT K, without x....insuff
(2) x is not 0 then k has to be +1/3 or -1/3...insuff
If K>0 AND x not equal to 0 then k has to be 1/3
SO OA:C
if x = 0 then k can be any value
(1) no use OF KNOWING ABOUT K, without x....insuff
(2) x is not 0 then k has to be +1/3 or -1/3...insuff
If K>0 AND x not equal to 0 then k has to be 1/3
SO OA:C
19 Sep 2019, 22:01
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If \((3k)^x\) = 1, what is the value of k ?
\((3k)^x\) = 1 =>after analysis, we can say that k=any value and x=0, e, only then the equation could be equal to 1
(1) k> 0
k could be any number from 1 to ∞. INSUFFICIENT!
(2) x is a positive
From our analysis, we know x has to be zero. Since we don't know anything about k, can't comment. INSUFFICIENT!
(1) + (2)
k> 0 and x is a positive
only when k=\(\frac{1}{3}\) and x=1 satisfies the equation \((3k)^x\) = 1. Hence, k=\(\frac{1}{3}\). SUFFICIENT!
IMO answer is option C
\((3k)^x\) = 1 =>after analysis, we can say that k=any value and x=0, e, only then the equation could be equal to 1
(1) k> 0
k could be any number from 1 to ∞. INSUFFICIENT!
(2) x is a positive
From our analysis, we know x has to be zero. Since we don't know anything about k, can't comment. INSUFFICIENT!
(1) + (2)
k> 0 and x is a positive
only when k=\(\frac{1}{3}\) and x=1 satisfies the equation \((3k)^x\) = 1. Hence, k=\(\frac{1}{3}\). SUFFICIENT!
IMO answer is option C
