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Bunuel
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The question can be simplified to is b>a?
Here's how: from the equation given, we can simplify it to b(a-2p)>a(b-2p)
If you further simplify it, it'd be ab-2bp>ab-2ap --> b>a

Now looking at 1 and 2, 2 answers the question directly.

Answer: B
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Here is my take on it

I) p>0
But a/b is ratio
And we dont know whether a-2p/b-2p would be greater than a/b
Depends on a>b then no
a<b then yes

II) no info about p so insufficient

Together we can answer question

C is answer

Eg ldt p=1 a=-3 b=-2

a-2p/b-2p= 5/4

a/b=3/2
3/2 is greater than 5/4


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Bunuel
If \(a<0\) and \(b<0\) , is \(\frac{(a-2p)}{(b-2p)}\) \(>\) \(\frac{a}{b}\) ?


(1) \(p>0\)

(2) \(a<b\)

We can slightly modify (a-2p)/(b-2p) > a/b by bringing a/b to the left side. Then we get:

(a-2p)/(b-2p) - a/b > 0 OR {ab - 2pb - ab + 2pa}/{b*(b-2p)} > 0 OR {2p*(a-b)}/{b*(b-2p)} > 0
Now since b is negative, we can multiply both sides by b and change the sign of inequality. So now the question is basically asking whether:

{2p*(a-b)}/{b-2p} < 0 or not.

(1) p > 0
So 2p is positive, and denominator (b-2p) is negative (since b is already negative). But we dont know whether (a-b) in the numerator is negative or positive. Not sufficient.

(2) a < b
So (a-b) in the numerator is negative. But we dont know whether '2p' and 'b-2p' are negative or positive. Not sufficient.

Combining the statements, p is positive. This makes '2p' as positive, 'b-2p' as negative. And since a < b this makes 'a-b' as negative.
So overall {2p*(a-b)}/{b-2p} becomes positive. And this gives NO as an answer to the question asked. Sufficient.

Hence C answer
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Hello from the GMAT Club BumpBot!

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