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Answer is C.
For a^b = 16 we can have 2^4, (-2)^4, 4^2, (-4)^2, 16^1. For 2^4 and 4^2 we get |a-b| = 2. For 16^1, |a-b| = 15. For (-2)^4 and (-4)^2 we |a-b| = 6. So, we have 3 different answers. Let us see if the statements help us narrow down to one answer.

Statement 1 : This eliminates the option where a=16, b=1. But still |a-b| can be 2 or 6.
Insufficient.

Statement 2 : This eliminates options with negative values of a. Still we have |a-b| = 2 or 15.
Insufficient.

Combining both, we have only |a-b| = 2. Hence together they are sufficient. So answer is C.

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Bunuel
If a and b are integers and \(a^b = 16\), \(|a-b| = ?\)

(1) \(b ≠ 1\)
(2) \(a > 0\)


Project DS Butler Data Sufficiency (DS3)


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This question is a part of Are You Up For the Challenge: 700 Level Questions collection.
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Bunuel
If a and b are integers and \(a^b = 16\), \(|a-b| = ?\)

(1) \(b ≠ 1\)
(2) \(a > 0\)


Breaking Down the Info:

We may have \(4^2 = (-4)^2 = 2^4 = (-2)^4 = 16^1 = 16\)

Rephrase the question:

What is the positive difference between a and b? Note that some of our options give the same positive difference.

Statement 1 Alone:

This only rules out one option; we still have 4 options which can give us a positive difference of 6 or 2. Then this statement is insufficient.

Statement 2 Alone:

We can have \(4^2 = 2^4 = 16^1 = 16\). We still have two difference positive differences, so this statement is insufficient.

Both Statements Combined:

Now we ruled out \(16^1 = 16\), so we have only \(4^2 = 2^4 = 16\) which both give a positive difference of 2. Then combined it is sufficient.

Answer: C
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