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Bunuel

Tough and Tricky questions: Exponents.



If a and b are positive integers and x = 4^a and y = 9^b, which of the following is a possible units digit of xy?

A. 1
B. 4
C. 5
D. 7
E. 8

Check Units digits, exponents, remainders problems directory in our Special Questions Directory.
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Bunuel

Tough and Tricky questions: Exponents.



If a and b are positive integers and x = 4^a and y = 9^b, which of the following is a possible units digit of xy?

A. 1
B. 4
C. 5
D. 7
E. 8

Cyclicity of 4=2

4^1=4
4^2=16
4^3=64
Cycicity of 9 is 2
9^1=9
9^2=81
9^3=729

So possible options 4*9 =36 or 1*4=4

Ans B
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\(4^1 = 4 .......................... 9^1 = 9\)

\(4^2 = 16 ......................... 9^2 = 81\)

\(4^3 = 64 ........................... 9^3 = 729\)

Total combinations possible are four which are (4*9) (4*1) (6*9) (6*1)

Answer = 4 = B
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x=4^a where a is a positive integer will have a units digit of 4 or 6

4^1 = 4 -> units digit 4
4^2 =16 -> units digit 6
4^3 = 64 -> units digit 4

y=9^b where b is a positive integer will have a units digit of 9 or 1.

9^1 = 9 -> units digit 9
9^2 = 81 -> units digit 1
9^3 =729 -> units digit 9

Product of xy will have units digit of 4*9=36=units digit 6 , 4*1=4=units digit 4 , 6*9=54=units digit 4 or 6*1=6=units digit 6.

So xy can have either units digit 4 or 6.

Answer B
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a, b are positive integers
x = 4^a ; y = 9^b
a = 4 or 6
b = 1 or 9
xy = 4 or 6
B
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XY = 2^2a x 3^2b
= Even X Odd = Even

Mean XY divisible by 2 and XY divisible by 2 its unit digit shall be multiple of 2

Also we we have prime factorized XY and it's power is even mean the number will be perfect square

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