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I cannot be true in all cases (e.g. 91,93,95 are consecutive odd positive integers but none is a prime).
For II, the case for 1,3,5 does not hold (i.e. for this case, ab<c, whereas ab>c for all other cases)
III must be true since a+b+c= 3b => b = (1/2)*(a+c), which must be true since b, being a consecutive odd integer between a and c, must always be the average of a and c.

A it is.
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Do we have to remember such things or is there any way to know that after 90 , there are number not prime.


I wrote till 50 and realized that either of the number was prime and selected "1 " as option.
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But 1 is not a prime number. Isn't it?
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But 1 is not a prime number. Isn't it?

Yes, 1 is not a prime number. But what this has to do with the question?
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Oh I got it. I used 1, 3, 5 as a test for I and II. That's an error on my part.
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If a, b, and c are consecutive odd positive integers and a<b<c, which of the following must be true?

I. at least one of the three numbers is prime
II. ab>c
III. a + b + c = 3b

A. III only
B. I and II only
C. I and III only
D. II and III only
E. I, II, and III

The Case 91,93,95 where there are no prime nos. is tested here. as their is only one prime number between 90 to 99 ie 97. And hence option A
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115, 117(13*9), 119(17*7) are not prime numbers
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Is this a good math?!
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Seems like a question testing obscure knowledge that won't be asked for on the GMAT.
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OE:

Statement I is generally true for numbers below 100, but once you investigate higher numbers, you find sets of consecutive odd positive integers in which none are prime (for example, 121 (divisible by 11), 123 (divisible by 3), 125 (divisible by 5)). Statement II is true for all sets of consecutive odd positive integers except the lowest, 1, 3 and 5. (1 * 3)<5. Only Statement III is always necessarily true: a is 2 less than b, and c is 2 greater than b. Those differences cancel each other out when you multiply the sum of the set by any positive integer, yielding three times the median. (This property is also related to the rule that, in an evenly spaced set, the median and the mean are the same.)
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