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# If a person purchases 15 of the 3,000 tickets sold in a

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Intern
Joined: 24 Feb 2013
Posts: 12
Location: Argentina
WE: Project Management (Energy and Utilities)
If a person purchases 15 of the 3,000 tickets sold in a  [#permalink]

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Updated on: 23 May 2013, 09:19
00:00

Difficulty:

5% (low)

Question Stats:

86% (01:08) correct 14% (00:58) wrong based on 125 sessions

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If a person purchases 15 of the 3,000 tickets sold in a raffle that awards one prize, what is the probability that this person will not win?

(A) 0
(B) 1/200
(C) 1/2
(D) 199/200
(E) 1

Originally posted by grotten on 23 May 2013, 08:43.
Last edited by Bunuel on 23 May 2013, 09:19, edited 1 time in total.
Renamed the topic and edited the question.
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Location: Italy
Concentration: Finance, Entrepreneurship
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23 May 2013, 08:46
Probability of winning with one ticket is $$\frac{1}{3000}$$, so the probability of winning with $$15$$ tickets is $$\frac{15}{3000}$$.

$$P(lose)=1-P(win)=1-\frac{15}{3000}=\frac{2985}{3000}=\frac{199}{200}$$
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Intern
Joined: 24 Feb 2013
Posts: 12
Location: Argentina
WE: Project Management (Energy and Utilities)

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23 May 2013, 08:48
Simple problem...
It can be resolved by using common sense ..

A - Probability = 0 means the person will always WIN !! Incorrect
E - Prob = 1 means the person will never win!! Incorrect
C - Prob = 1/2 means the person will win half the times.. A bit to much buying anly 15 tickets out of 3000
B- Prob = 1/200 mean the person will almost always win.. same as C

Exp
prob to win = 15/3000 = 0.005 = 1/200
So... 200/200 - 1/200 = 199/200 !
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Joined: 20 Jul 2012
Posts: 112
Location: India
WE: Information Technology (Computer Software)
Re: If a person purchases 15 of the 3,000 tickets sold in a  [#permalink]

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05 Oct 2013, 00:04
grotten wrote:
If a person purchases 15 of the 3,000 tickets sold in a raffle that awards one prize, what is the probability that this person will not win?

(A) 0
(B) 1/200
(C) 1/2
(D) 199/200
(E) 1

Is it actually a 600-700 level problem.? We need not solve this question
0 and 1 cannot be the probability as 0 implies that person will surely win -The person has just 15 tickets..not all so out.. 1 cannot be the probablity as it implies that the person will surely lose..but looking at the numbers he has 15 tickets so he may win also...so out
1/2 can be the probability if he has 50% tickets which is not the case so out
now left with (B) and (E)
looking at the nos (b) will be the probabilty of the person winning ...so (E) is the answer..
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Intern
Joined: 22 Nov 2012
Posts: 2
Re: If a person purchases 15 of the 3,000 tickets sold in a  [#permalink]

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02 Nov 2013, 17:01
I agree that minimal arithmetic needs to be done.

Looking at the answers, we can quickly eliminate 0 (no chance of him winning) and 1 (definite chance of winning).

The 50:50 chance of him winning (ie. 1/2) means he needs to purchase 1500 tickets NOT 15.

So we're left with 1/200 & 199/200

15/3000 = 1/200......the probability of him winning.

Hence the answer is 199/200 by elimination.
Re: If a person purchases 15 of the 3,000 tickets sold in a   [#permalink] 02 Nov 2013, 17:01
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