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Bunuel
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None should be answer

a3b=ab3
gives a2=b2
a=+-b
ab unequals 0
nothing can be concluded precisely. Thus E should be answer.
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Bunuel
If ab ≠ 0 and \(a^3b = ab^3\), then which of the following must be true?

I. a = b
II. a = –b
III. ab = 1

A. None
B. I only
C. III only
D. I and III only
E. I, II, and III


­
a3b - ab3 = 0
ab (a2 - b2) = 0
As per the above statement , ab =0 or (a2-b2) =0
But, in the question it’s mentioned ab is NOT equal to 0.

(a2-b2) must be zero.
(a+b) (a-b) = 0
Therefore, either a = b or a=-b.

ab can be any integer value. Can be 1 also.

If the question is could be true, then all three options can be true. Option E.

But, MUST BE TRUE Is the question asked. Hence option A
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a^3*b=a*b^3
(a^3*b)-(a*b^3)=0
ab(a^2-b^2)=0
ab ≠ 0 , so (a-b)(a+b)=0
either (a=b) or (a= -b)
The question asks must be true, a can be either equal to b or -b, hence all the statements could be true but can’t be must be true
I. a = b
II. a = –b
III. ab = 1

Answer: A
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The question ask for must be true

a^3*b=a*b^3
ab(a^2)=ab(b^2)
a^2=b^2

(a,b) could be both positive, e.g. (10,10), and still fits the equation
(a,b) could be one positive and one negative, e.g. (10,-10); (-10,10), and still fits the equation
(a,b) could be both negative, e.g. (-10,-10), and still fits the equation

Therefore, (I) & (II) can be eliminated as the statement isn't "must be true" for the equation.

we can only conclude that ab=ab, but doesn't necessary means ab=1
Therefore, (III) can be eliminated as well.

Hence, option (A) None is the correct answer.
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