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If ab 0, then a^(-1) + b^(-1) =

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carbazzy
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If ab 0, then a^(-1) + b^(-1) = [#permalink] New post  Updated on: 21 Jul 2022, 02:27
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If \(ab ≠ 0\), then \(a^{-1} + b^{-1}=\)

A. a + b
B. -(a + b)
C. 1/(a + b)
D. 2/(a + b)
E. (a + b)/ab
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Originally posted by carbazzy on 05 Aug 2019, 13:24.
Last edited by Bunuel on 21 Jul 2022, 02:27, edited 3 times in total.
Renamed the topic and edited the question.
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BrentGMATPrepNow
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Re: If ab 0, then a^(-1) + b^(-1) = [#permalink] New post  05 Aug 2019, 13:32
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You might want to recheck your post.
I think you meant to write "a" instead of "2"

Cheers,
Brent
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BrentGMATPrepNow
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Re: If ab 0, then a^(-1) + b^(-1) = [#permalink] New post  05 Aug 2019, 13:38
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carbazzy wrote:
If ab not equal to 0, then \(a^-1 + b^-1\) =

a)a+b
b)-(a+b)
c)\(1/a+b\)
d)\(2/a+b\)
e)\(a+b/ab\)


Key concept: \(x^{-n}=\frac{1}{x^n}\)

\(a^{-1} + b^{-1} = \frac{1}{a}+\frac{1}{b}\)

\(= \frac{b}{ab}+\frac{a}{ab}\)

\(= \frac{b+a}{ab}\)

Answer: E

Cheers,
Brent
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carbazzy
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Re: If ab 0, then a^(-1) + b^(-1) = [#permalink] New post  05 Aug 2019, 13:52
carbazzy wrote:
If ab not equal to 0, then \(a^-1 + b^-1\) =

a)a+b
b)-(a+b)
c)\(1/a+b\)
d)\(2/a+b\)
e)\(a+b/ab\)




Thanks so much for all the replies. Made a ton of silly mistakes today!
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Re: PS-GMAT prep [#permalink] New post  21 Jul 2022, 02:27
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