If each student gets at least one pencil in the exam hall, then Total number of students is same as students who get atleast one pencil
\(P = \frac{{Student gets exactly 1 Pencil}}{{All students} }\) OR \(\frac{{Student gets exactly 1 Pencil}}{{Students get atleast one pencil} }\)
Statement 1
Given 110 students are expected to get at least one pencil, All students = 110
\(P = \frac{{Student gets exactly 1 Pencil}}{{All students} }\)
\(P = \frac{{Student gets exactly 1 Pencil}}{110 }\)
We don't know the numerator
Insufficient
Statement 2
Given 60 students are expected to get at least two pencils
We don't know anything about students who gets exactly one pencil
Insufficient
Combined, we have students who get at least one pencil = 110 and students who get at least two pencil = 60.
This means exactly students who get exactly one pencil = 110-60 = 50
Using 1, we know
\(P = \frac{{Student gets exactly 1 Pencil}}{110 }\)
P = 50/110
Answer C
Bunuel
If each student gets at least one pencil in the exam hall, what is the probability that a student gets exactly one pencil in the exam hall?
(1) 110 students are expected to get at least one pencil.
(2) 60 students are expected to get at least two pencils.