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If f(x) = x^2 – 1, what is the value of f(y) + f(–1)?

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V
Joined: 02 Sep 2009
Posts: 47903
If f(x) = x^2 – 1, what is the value of f(y) + f(–1)?  [#permalink]

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New post 27 Jul 2018, 01:12
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

88% (00:32) correct 13% (00:48) wrong based on 40 sessions

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Manager
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S
Joined: 19 Nov 2017
Posts: 144
Location: India
Schools: ISB
GMAT 1: 670 Q49 V32
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Re: If f(x) = x^2 – 1, what is the value of f(y) + f(–1)?  [#permalink]

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New post 27 Jul 2018, 01:20
\(f(x) = x^2 - 1\)
\(f(y) = y^2 - 1\)
\(f(-1) = (-1)^2 - 1 = 1 - 1 = 0\)

\(f(y) + f(-1) = f(y) = y^2 - 1\)
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Re: If f(x) = x^2 – 1, what is the value of f(y) + f(–1)?  [#permalink]

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New post 27 Jul 2018, 02:04
= f(y) + f(−1)
= ( y^2 - 1) + ( (-1)^2 - 1 )
= y^2 - 1 + 0
= y^2 - 1

Hence, A.
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Joined: 24 Dec 2017
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Re: If f(x) = x^2 – 1, what is the value of f(y) + f(–1)?  [#permalink]

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New post 27 Jul 2018, 05:10
f(x) = x^2 – 1
f(y) = y^2 - 1
f(-1) = (-1)^2 - 1 = 0

f(y) + f(–1) = y^2 - 1

IMO A
Re: If f(x) = x^2 – 1, what is the value of f(y) + f(–1)? &nbs [#permalink] 27 Jul 2018, 05:10
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