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Bunuel
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a is 2 and b is 1.5 which makes 6
So we know what is a and b
16*to 6 96

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MonishBhawale
E
f(x,y)=x2y
f(a,b)= a2b=6
a2b= 1*6
A=1,b=6
F(2a,4b)=(2a)^2*4b
= (2*1)^2*4*6
=96
E

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Also could be ,a 2 and b 1.5
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Given that \(f(x, y) = x^2y\) and \(f(a, b) = 6\) and we need to find the value of \(f(2a, 4b)\)

To find f(a, b) we need to compare what is inside the bracket in f(a, b) and f(x, y)
=> We need to substitute x with a and y with b in \(f(x, y) = x^2y\) to get the value of f(a, b)

=> \(f(a, b) = a^2b\) = 6 given

Similarly, \(f(2a, 4b)\) = \((2a)^2*(4b)\) = \(4a^2 * 4b\) = 16 * \(a^2b\) = 16*6 = 96

So, Answer will be E
Hope it helps!

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