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Re: If gasoline costs $1.09 per gallon and alcohol costs $1.81, what fract [#permalink]
Can someone please explain how we calculate the fraction/ratio of the liquids from statement 2?
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Re: If gasoline costs $1.09 per gallon and alcohol costs $1.81, what fract [#permalink]
Hello Guys,

Someone solved the equation by any chance, just to see how to calculate ?

Thank you
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Re: If gasoline costs $1.09 per gallon and alcohol costs $1.81, what fract [#permalink]
blanchif wrote:
Hello Guys,

Someone solved the equation by any chance, just to see how to calculate ?

Thank you


Hey, blanchif I don't know if you ended up figuring it out on your own but here are two ways to solve this question.

Method 1: Algebra

Building off of the answer by Skywalker18

\(1.22(a+g) =( 1.09 g + 1.81 a )\)

leads you to put the a terms on one side and g terms on the other.

\(0.13g=0.59a\)

\(\frac{a}{g}=\frac{0.13}{0.59}\)

That is enough information to give you % composition.

Method 2: Alligation

Just use the relative scale of the price per gallon, since price per gallon is technically a portion of a weighted average.

\(\frac{|1.22 - 1.09|}{|1.22 - 1.81|} = \frac{0.13}{0.59}\)


Essentially for these problems, as long as you have the weighted average and the individual averages, you should be able to come up with their compositional ratios.
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Re: If gasoline costs $1.09 per gallon and alcohol costs $1.81, what fract [#permalink]
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