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| As we have |x +3| in the equation so we will have two cases | |
| -Case 1: x + 3 ≥ 0 => x ≥ -3 => |x + 3| = x + 3 => x + 3 = 4x - 5 => 3x = 8 => x = 8/3 But condition was x ≥ -3 and 8/3 ≥ -3 => x = 8/3 is a SOLUTION | -Case 2: x + 3 ≤ 0 => x ≤ - 3 => |x + 3| = -(x + 3) => -(x + 3) = 4x - 5 => 5x = 2 => x = 2/5 But condition was x ≤ 0 and 2/5 is NOT ≤ 0 => NO SOLUTION |
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