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Helium
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If m = 3x + 4y for x, y > 0. Find the minimum value of m. Updated on: 26 Aug 2018, 02:42
Originally posted by Helium on 25 Aug 2018, 19:36.
Last edited by Bunuel on 26 Aug 2018, 02:42, edited 5 times in total.
Renamed the topic and edited the question.
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If m = 3x + 4y for x, y > 0. Find the minimum value of m.


(1) When m is minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

(2) xy = 27/4

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If m = 3x + 4y for x, y > 0. Find the minimum value of m. Updated on: 25 Aug 2018, 20:56
Originally posted by rahul16singh28 on 25 Aug 2018, 20:06.
Last edited by rahul16singh28 on 25 Aug 2018, 20:56, edited 3 times in total.
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Harshgmat
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27
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Hi Harshgmat

Statement I:

\(25 m^2/16*9 = 225/4\)

m = 18

Statement II:

\(x = 27/4y\)
\(m = 81/4y + 4y\)
\(y = 9/4, x = 3\)
\(m = 18\).

Hence, D.
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If m = 3x + 4y for x, y > 0. Find the minimum value of m. Updated on: 25 Aug 2018, 20:57
Originally posted by Helium on 25 Aug 2018, 20:44.
Last edited by Helium on 25 Aug 2018, 20:57, edited 1 time in total.
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rahul16singh28
Harshgmat
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27

Hi Harshgmat

Not sure, if we are missing anything in the question or if there is any flaw in my logic.

Statement I:

\(25 m^2/16*9 = 225/4\)

m = 18

Statement II:

\(x = 27/y\)
\(m = 81/y + 4y\)
\(y = 9/2, x = 6\)
\(m = 36\).

For the same value of m, I am getting two different answers from the two statements. But as Statement I says, the distance is minimum between the two Intercepts - so, m(min) = 18. Hence, A.
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Hi rahul16singh28

Thanks...Edited the typo.

Does it make sense now...

Your approach for statement 2) is elegant!!
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If m = 3x + 4y for x, y > 0. Find the minimum value of m. 25 Aug 2018, 20:50
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Harshgmat
rahul16singh28
Harshgmat
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27

Hi Harshgmat

Not sure, if we are missing anything in the question or if there is any flaw in my logic.

Statement I:

\(25 m^2/16*9 = 225/4\)

m = 18

Statement II:

\(x = 27/y\)
\(m = 81/y + 4y\)
\(y = 9/2, x = 6\)
\(m = 36\).

For the same value of m, I am getting two different answers from the two statements. But as Statement I says, the distance is minimum between the two Intercepts - so, m(min) = 18. Hence, A.

Hi rahul16singh28

Thanks...Edited the typo.

Does it make sense now...

Your approach for sentence 2) is elegant!!
Show more

Yeah.. now the answer should be D:).. Thanks..!!
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If m = 3x + 4y for x, y > 0. Find the minimum value of m. 25 Aug 2018, 22:38
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Harshgmat
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27/4
Show more


The question is flawed. It is nowhere mentioned that x and y are positive so xy =27/4 can mean x= -1000 and y = -27/4000
So 3x+4y = 3*-1000+4*(-27/4000)=-3000-27/1000
Ofcourse the value can go to ' - infinity'

Also statement I is awkward
1) WHEN min distance ....
When seems to be giving some scenario and not a condition..
So it should have been merely
1) min distance....
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If m = 3x + 4y for x, y > 0. Find the minimum value of m. 25 Aug 2018, 22:56
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chetan2u
Harshgmat
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27/4


The question is flawed. It is nowhere mentioned that x and y are positive so xy =27/4 can mean x= -1000 and y = -27/4000
So 3x+4y = 3*-1000+4*(-27/4000)=-3000-27/1000
Ofcourse the value can go to ' - infinity'

Also statement I is awkward
1) WHEN min distance ....
When seems to be giving some scenario and not a condition..
So it should have been merely
1) min distance....
Show more

chetan2u

You are right...

if it is given that x, y >0 then does that make given statements sufficient ?

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