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If m = 3x + 4y for x, y > 0. Find the minimum value of m.

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If m = 3x + 4y for x, y > 0. Find the minimum value of m.  [#permalink]

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New post Updated on: 26 Aug 2018, 02:42
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Difficulty:

  55% (hard)

Question Stats:

55% (00:58) correct 45% (01:20) wrong based on 11 sessions

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If m = 3x + 4y for x, y > 0. Find the minimum value of m.


(1) When m is minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

(2) xy = 27/4

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Originally posted by Helium on 25 Aug 2018, 19:36.
Last edited by Bunuel on 26 Aug 2018, 02:42, edited 5 times in total.
Renamed the topic and edited the question.
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Re: If m = 3x + 4y for x, y > 0. Find the minimum value of m.  [#permalink]

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New post Updated on: 25 Aug 2018, 20:56
Harshgmat wrote:
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27


Hi Harshgmat

Statement I:

\(25 m^2/16*9 = 225/4\)

m = 18

Statement II:

\(x = 27/4y\)
\(m = 81/4y + 4y\)
\(y = 9/4, x = 3\)
\(m = 18\).

Hence, D.
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Originally posted by rahul16singh28 on 25 Aug 2018, 20:06.
Last edited by rahul16singh28 on 25 Aug 2018, 20:56, edited 3 times in total.
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Re: If m = 3x + 4y for x, y > 0. Find the minimum value of m.  [#permalink]

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New post Updated on: 25 Aug 2018, 20:57
rahul16singh28 wrote:
Harshgmat wrote:
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27


Hi Harshgmat

Not sure, if we are missing anything in the question or if there is any flaw in my logic.

Statement I:

\(25 m^2/16*9 = 225/4\)

m = 18

Statement II:

\(x = 27/y\)
\(m = 81/y + 4y\)
\(y = 9/2, x = 6\)
\(m = 36\).

For the same value of m, I am getting two different answers from the two statements. But as Statement I says, the distance is minimum between the two Intercepts - so, m(min) = 18. Hence, A.


Hi rahul16singh28

Thanks...Edited the typo.

Does it make sense now...

Your approach for statement 2) is elegant!!
_________________
Everything will fall into place…

There is perfect timing for
everything and everyone.
Never doubt, But Work on
improving yourself,
Keep the faith and
Stay ready. When it’s
finally your turn,
It will all make sense.

Originally posted by Helium on 25 Aug 2018, 20:44.
Last edited by Helium on 25 Aug 2018, 20:57, edited 1 time in total.
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Re: If m = 3x + 4y for x, y > 0. Find the minimum value of m.  [#permalink]

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New post 25 Aug 2018, 20:50
Harshgmat wrote:
rahul16singh28 wrote:
Harshgmat wrote:
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27


Hi Harshgmat

Not sure, if we are missing anything in the question or if there is any flaw in my logic.

Statement I:

\(25 m^2/16*9 = 225/4\)

m = 18

Statement II:

\(x = 27/y\)
\(m = 81/y + 4y\)
\(y = 9/2, x = 6\)
\(m = 36\).

For the same value of m, I am getting two different answers from the two statements. But as Statement I says, the distance is minimum between the two Intercepts - so, m(min) = 18. Hence, A.


Hi rahul16singh28

Thanks...Edited the typo.

Does it make sense now...

Your approach for sentence 2) is elegant!!


Yeah.. now the answer should be D:).. Thanks..!!
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Re: If m = 3x + 4y for x, y > 0. Find the minimum value of m.  [#permalink]

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New post 25 Aug 2018, 22:38
Harshgmat wrote:
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27/4



The question is flawed. It is nowhere mentioned that x and y are positive so xy =27/4 can mean x= -1000 and y = -27/4000
So 3x+4y = 3*-1000+4*(-27/4000)=-3000-27/1000
Ofcourse the value can go to ' - infinity'

Also statement I is awkward
1) WHEN min distance ....
When seems to be giving some scenario and not a condition..
So it should have been merely
1) min distance....
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Re: If m = 3x + 4y for x, y > 0. Find the minimum value of m.  [#permalink]

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New post 25 Aug 2018, 22:56
chetan2u wrote:
Harshgmat wrote:
If m = 3x + 4y Find the minimum value of m.

1) When minimum distance between X and Y intercepts in a co-ordinate plane is 15/2 .

2) xy = 27/4



The question is flawed. It is nowhere mentioned that x and y are positive so xy =27/4 can mean x= -1000 and y = -27/4000
So 3x+4y = 3*-1000+4*(-27/4000)=-3000-27/1000
Ofcourse the value can go to ' - infinity'

Also statement I is awkward
1) WHEN min distance ....
When seems to be giving some scenario and not a condition..
So it should have been merely
1) min distance....


chetan2u

You are right...

if it is given that x, y >0 then does that make given statements sufficient ?
_________________
Everything will fall into place…

There is perfect timing for
everything and everyone.
Never doubt, But Work on
improving yourself,
Keep the faith and
Stay ready. When it’s
finally your turn,
It will all make sense.
GMAT Club Bot
Re: If m = 3x + 4y for x, y > 0. Find the minimum value of m.   [#permalink] 25 Aug 2018, 22:56
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If m = 3x + 4y for x, y > 0. Find the minimum value of m.

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