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16 Dec 2019, 01:34
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If m is a positive integer and m = x + y + 2z, is m odd ?
(1) x and y are consecutive positive integers.
(2) 4z is even.
Are You Up For the Challenge: 700 Level Questions
(1) x and y are consecutive positive integers.
(2) 4z is even.
Are You Up For the Challenge: 700 Level Questions
16 Dec 2019, 02:14
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m - positive
m = x + y + 2z ....
Pre-calculating: we are sure that 2z is even. If anyone from X or Y is odd then, m will be odd. If both are odd/even, then m will be even.
Statement 1: - x and y are consecutive pos. int - take example of 1&2, 2&3 ... the sum will be always ODD - Sufficient
A D /B C E
Statement 2: - 4z is even. We already know z does not have an importance to find whether m is odd or even. Hence, insufficient
'A' is the winner
m = x + y + 2z ....
Pre-calculating: we are sure that 2z is even. If anyone from X or Y is odd then, m will be odd. If both are odd/even, then m will be even.
Statement 1: - x and y are consecutive pos. int - take example of 1&2, 2&3 ... the sum will be always ODD - Sufficient
A D /
Statement 2: - 4z is even. We already know z does not have an importance to find whether m is odd or even. Hence, insufficient
'A' is the winner
Bunuel
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15 Jan 2020, 13:35
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Z is integer or postive or negative not been given.
1----z = 2 m = odd
z = -1/2 m = even
2. insuff
combined
z= -3/2 m = even
z= 2 m = odd
E
1----z = 2 m = odd
z = -1/2 m = even
2. insuff
combined
z= -3/2 m = even
z= 2 m = odd
E
