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If m is a positive integer and m = x + y + 2z, is m odd ?

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If m is a positive integer and m = x + y + 2z, is m odd ?  [#permalink]

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New post 16 Dec 2019, 00:34
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

28% (01:59) correct 72% (01:08) wrong based on 36 sessions

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Re: If m is a positive integer and m = x + y + 2z, is m odd ?  [#permalink]

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New post 16 Dec 2019, 01:14
m - positive
m = x + y + 2z ....
Pre-calculating: we are sure that 2z is even. If anyone from X or Y is odd then, m will be odd. If both are odd/even, then m will be even.

Statement 1: - x and y are consecutive pos. int - take example of 1&2, 2&3 ... the sum will be always ODD - Sufficient

A D / B C E

Statement 2: - 4z is even. We already know z does not have an importance to find whether m is odd or even. Hence, insufficient

'A' is the winner

Bunuel wrote:
If m is a positive integer and m = x + y + 2z, is m odd ?

(1) x and y are consecutive positive integers.
(2) 4z is even.


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Re: If m is a positive integer and m = x + y + 2z, is m odd ?  [#permalink]

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New post 15 Jan 2020, 12:35
Z is integer or postive or negative not been given.

1----z = 2 m = odd
z = -1/2 m = even

2. insuff
combined
z= -3/2 m = even
z= 2 m = odd

E
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Re: If m is a positive integer and m = x + y + 2z, is m odd ?   [#permalink] 15 Jan 2020, 12:35
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