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Re: If n = 2.0453 and n* is the decimal obtained by rounding n to the near [#permalink]
n= 2.0453
n*= rounded to nearest hundredth = 2.05 ( as next digit is 5)

so n*-n = 2.05 - 2.0453
= 0.047

Choice D
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Re: If n = 2.0453 and n* is the decimal obtained by rounding n to the near [#permalink]
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Bunuel wrote:
If n = 2.0453 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?

(A) -0.0053

(B) -0.0003

(C) 0.0007

(D) 0.0047

(E) 0.0153


Kudos for a correct solution.


Rounding off to nearest hundredth=2.05
And, 2.05-2.0453=0.0047
Answer D
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Re: If n = 2.0453 and n* is the decimal obtained by rounding n to the near [#permalink]
Expert Reply
Bunuel wrote:
If n = 2.0453 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?

(A) -0.0053

(B) -0.0003

(C) 0.0007

(D) 0.0047

(E) 0.0153


Kudos for a correct solution.


VERITAS PREP OFFICIAL SOLUTION

A quick note on place value nomenclature:

Given a decimal 345.789, we know that 5 represents the units digit, 4 the tens digit and 3 the hundreds digit. Also, 7 represents the tenths digit, 8 the hundredths digit and 9 the thousandths digit and so on…

Now let’s go back to this question:

n = 2.0453

We need to round n to the nearest hundredth which means we will retain 2 digits after the decimal. The third digit after the decimal is 5 so 2.0453 rounded to the nearest hundredth is 2.05.

Thus n* – n = 2.05 – 2.0453 = 0.0047

Answer (D)

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Re: If n = 2.0453 and n* is the decimal obtained by rounding n to the near [#permalink]
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