UB001 wrote:

If n and k are integers and (-2)n^5 > 0, is k^37 < 0?

1. (nk)^z > 0, where z is an integer that is not divisible by two

2. k < n

So, before solving the question, lets brain storm over it a bit

If n and k are integers and (-2)n^5 > 0

That will imply that n will be -ive

(-2) * (-I)^5 will only give something > 0

Statement (1)

(nk)^z > 0, where z is an integer that is not divisible by two

z will be 1,3,5,7

here k will be - ive, (-n* -k)^Odd Integer, will give something > 0

When value of k^37 < 0, is put back in the question, it will be sufficient.

Statement (2)

k < n, Since n is -ive

k will be -ive

(-ive k)^ 37 < 0, will always be less than 0, it will be sufficient

Answer D

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