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If n is a positive integer, what is the units digit of n?
(1) the units digit of \((n+4)^2\) is 4
(2) the units digit of \((n+3)^2\) is 1
(1) the units digit of \((n+4)^2\) is 4
(2) the units digit of \((n+3)^2\) is 1
Any other alternative solution
16 Jun 2013, 00:13
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fozzzy
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Hope it helps.
15 Jun 2013, 23:18
Kudos
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From statement 1 we get 2 values for n 4,8
\((4+4)^2\) = 4
\((8+4)^2\) = 4
From staement 2 we get 6,8
\((6+3)^2\) =1
\((8+3)^2\)= 1
so combined from 4,8 and 6,8
we get 8
\((4+4)^2\) = 4
\((8+4)^2\) = 4
From staement 2 we get 6,8
\((6+3)^2\) =1
\((8+3)^2\)= 1
so combined from 4,8 and 6,8
we get 8
