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andreagonzalez2k
yashikaaggarwal
An angle sustended from diameter to any point on circle make 90 degree angle.
Therefore ACD is 90
CAD is 20 (180 degree property)
Since BC and CD are equal.
Both triangles are similar.
Either of ABC or ACB can be 70 & 90 (no need to indulge much)
X will be 20.

Answer is B

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The answer is B but ABC and ACD triangles are not similar. BAC and CAD angles have same value, but the other four angles of the two triangles have all different values. For example, ABC angle is not a right one but ACD angle is (it can not be a right angle as the cord AC is not the diameter).
I never said ABC is right angled. I know it's not. I just kept answer short so it could be solved within a few seconds. Applying the original answers is time consuming process.
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andreagonzalez2k
yashikaaggarwal
An angle sustended from diameter to any point on circle make 90 degree angle.
Therefore ACD is 90
CAD is 20 (180 degree property)
Since BC and CD are equal.
Both triangles are similar.
Either of ABC or ACB can be 70 & 90 (no need to indulge much)
X will be 20.

Answer is B

Posted from my mobile device


The answer is B but ABC and ACD triangles are not similar. BAC and CAD angles have same value, but the other four angles of the two triangles have all different values. For example, ABC angle is not a right one but ACD angle is (it can not be a right angle as the cord AC is not the diameter).
I never said ABC is right angled. I know it's not. I just kept answer short so it could be solved within a few seconds. Applying the original answers is time consuming process.

Sure, but you said "Both triangles are similar." and they aren't.
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andreagonzalez2k

Sure, but you said "Both triangles are similar." and they aren't.
Dude, Its congurent. I apologize for misplacing a grave one word.

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yashikaaggarwal
An angle sustended from diameter to any point on circle make 90 degree angle.
Therefore ACD is 90
CAD is 20 (180 degree property)
Since BC and CD are equal.
Both triangles are similar congruent.
Either of ABC or ACB can be 70 & 90 (no need to indulge much)
X will be 20.

Answer is B

Posted from my mobile device

I have a question here, how are you proving the congruency?
We have no information about the angles of triangle ABC and only two sides of triangle ABC and ACD are equal.

chetan2u Pl. advise!
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RamseyGooner
yashikaaggarwal
An angle sustended from diameter to any point on circle make 90 degree angle.
Therefore ACD is 90
CAD is 20 (180 degree property)
Since BC and CD are equal.
Both triangles are similar congruent.
Either of ABC or ACB can be 70 & 90 (no need to indulge much)
X will be 20.

Answer is B

Posted from my mobile device

I have a question here, how are you proving the congruency?
We have no information about the angles of triangle ABC and only two sides of triangle ABC and ACD are equal.

chetan2u Pl. advise!

Triangles ABC and ACD are neither similar nor congruent. It is not necessary in order to solve the problem.
As AD is the diameter, angle ACD is 90º. So angle CAD is 20º. And as the inscribed angles CAD and BAC cover the same arc (because CD=BC), they are equal.
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RamseyGooner


I have a question here, how are you proving the congruency?
We have no information about the angles of triangle ABC and only two sides of triangle ABC and ACD are equal.

chetan2u Pl. advise!
I said triangle to be congruent because they share two sides and one angle.
BC = CD gives one angle equal in both triangle and the AC side is common.
But yes you can go with the arc approach too.
Whatever helps you to keep the approach for this type of question intact.
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RamseyGooner


I have a question here, how are you proving the congruency?
We have no information about the angles of triangle ABC and only two sides of triangle ABC and ACD are equal.

chetan2u Pl. advise!
I said triangle to be congruent because they share two sides and one angle.
BC = CD gives one angle equal in both triangle and the AC side is common.
But yes you can go with the arc approach too.
Whatever helps you to keep the approach for this type of question intact.


SSA (Side-Side-Angle) condition is not enough to probe that two triangles are congruent (is this case they AREN'T).
https://en.wikipedia.org/wiki/Congruence_(geometry)#Side-side-angle
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yashikaaggarwal
RamseyGooner


I have a question here, how are you proving the congruency?
We have no information about the angles of triangle ABC and only two sides of triangle ABC and ACD are equal.

chetan2u Pl. advise!
I said triangle to be congruent because they share two sides and one angle.
BC = CD gives one angle equal in both triangle and the AC side is common.
But yes you can go with the arc approach too.
Whatever helps you to keep the approach for this type of question intact.


SSA (Side-Side-Angle) condition is not enough to probe that two triangles are congruent (is this case they AREN'T).
https://en.wikipedia.org/wiki/Congruence_(geometry)#Side-side-angle
Well, it's mathematics.
The more deeper you go, the more you indulge.
We won't be needing to prove the actual congruency there.
There are always the alternate solutions.

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