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goodyear2013
Attachment:
Eye of the Tiger.jpg
If P, Q and R are the centers of circles P, Q, and R and the points P, Q, R and T all lie on the same line, what portion of circle P is shaded?

A. 3/16
B. 1/5
C. 6/25
D. 1/4
E. 3/8

Hi, I want to know why we don't get same answer using PQ = 2?
OE
Let us say that line segment RT has a length of 1. RT is the radius of circle R, so circle R has a radius of 1.
Line segment QT is the diameter of circle R, so it has a length of 2 (twice the radius of circle R). Segment QT also happens to be the radius of circle Q, which therefore has a radius of 2.
Line segment PT, being the diameter of circle Q, has a length of 4. Segment PT also happens to be the radius of circle P, which therefore has a radius of 4.
The question is asking us what fraction of circle P is shaded. The answer will be
(shaded area) ÷ (area of circle P)
The area of circle P is π(4)2, which equals 16π. The shaded area is just the area of circle Q (i.e. π(2)^2, which equals 4π) minus the area of circle R (i.e. π(1)^2, which equals π). Therefore, the answer to our question is
(4π - π) / 16π
Shaded region = area of circle Q-area of circle R
=pi*(QT)^2-pi*(RT)^2
but QT=2RT
pi*(QT^2-QT^2/4)------>pi*3/4QT^2
but again PT=2QT
substituting----->3/4*pi*(PT/2)^2
3/16*pi*PT^2------>3/16*area of circle P
Ans A
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goodyear2013
Attachment:
Eye of the Tiger.jpg
If P, Q and R are the centers of circles P, Q, and R and the points P, Q, R and T all lie on the same line, what portion of circle P is shaded?

A. 3/16
B. 1/5
C. 6/25
D. 1/4
E. 3/8

Hi, I want to know why we don't get same answer using PQ = 2?
OE
Let us say that line segment RT has a length of 1. RT is the radius of circle R, so circle R has a radius of 1.
Line segment QT is the diameter of circle R, so it has a length of 2 (twice the radius of circle R). Segment QT also happens to be the radius of circle Q, which therefore has a radius of 2.
Line segment PT, being the diameter of circle Q, has a length of 4. Segment PT also happens to be the radius of circle P, which therefore has a radius of 4.
The question is asking us what fraction of circle P is shaded. The answer will be
(shaded area) ÷ (area of circle P)
The area of circle P is π(4)2, which equals 16π. The shaded area is just the area of circle Q (i.e. π(2)^2, which equals 4π) minus the area of circle R (i.e. π(1)^2, which equals π). Therefore, the answer to our question is
(4π - π) / 16π


Bunuel why can't RT be 1/2? The largest square in this diagram is P, the second biggest, Q and the smallest R - so if the radius of r is 1/2 then the radius of Q is 1 and the radius of P is 2- but I don't understand why I can't get 3/8 using this method.
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Bunuel why can't RT be 1/2? The largest square in this diagram is P, the second biggest, Q and the smallest R - so if the radius of r is 1/2 then the radius of Q is 1 and the radius of P is 2- but I don't understand why I can't get 3/8 using this method.

You can do that way too. This is a ratio question so if you do math correctly you should get the same answer no matter what numbers you use. But how can I tell what you did incorrectly if you don't show your work?
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We know, QT = 2 RT and PT = 2 QT or PT = 4 RT.

Let RT = 1. So, QT = 2 and PT = 4

Now, area of circle P, Q and R will be 16π, 4π and π respectively.

From this we get that area of circle R is 1/4 area of circle Q and 1/16 of circle P. Also, area of circle Q is 1/4 area of circle P.

So area of shaded region = area of circle P - area of circle Q + area of circle R = 16π - 4π + π = 13π

Therefore, the portion of circle P which is shaded = (16π - 13π)/16π = 3/16.
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Let the circle with center P radius be x. Area P--Pi*(x2)
Then radius of circle with center Q is x/2. Area Q--Pi(x2/4)
With same method area of circle R--Pi*(x2/16)
Area of shaded region-- Pi (x2/4-x2/16)= Pi *(3x2/16)

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goodyear2013

If P, Q and R are the centers of circles P, Q, and R and the points P, Q, R and T all lie on the same line, what portion of circle P is shaded?

A. 3/16
B. 1/5
C. 6/25
D. 1/4
E. 3/8

Hi, I want to know why we don't get same answer using PQ = 2?
OE
Let us say that line segment RT has a length of 1. RT is the radius of circle R, so circle R has a radius of 1.
Line segment QT is the diameter of circle R, so it has a length of 2 (twice the radius of circle R). Segment QT also happens to be the radius of circle Q, which therefore has a radius of 2.
Line segment PT, being the diameter of circle Q, has a length of 4. Segment PT also happens to be the radius of circle P, which therefore has a radius of 4.
The question is asking us what fraction of circle P is shaded. The answer will be
(shaded area) ÷ (area of circle P)
The area of circle P is π(4)2, which equals 16π. The shaded area is just the area of circle Q (i.e. π(2)^2, which equals 4π) minus the area of circle R (i.e. π(1)^2, which equals π). Therefore, the answer to our question is
(4π - π) / 16π

Attachment:
Eye of the Tiger.jpg

Let the radius of circle R = 1 unit
So Radius of circle Q = 2 unit
Radius of circle P = 4 unit

Area of shaded region : pi(2^2) - pi(1^1) = 3pi
Area of circle P = pi(4^2 )= 16pi

So ratio of shaded region to Circle P = 3pi/16pi = 3/16

Answer A
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goodyear2013

If P, Q and R are the centers of circles P, Q, and R and the points P, Q, R and T all lie on the same line, what portion of circle P is shaded?

A. 3/16
B. 1/5
C. 6/25
D. 1/4
E. 3/8

We can let the radius of circles P, Q, and R be 4, 2, and 1, respectively. Therefore, the area of circle P is π(4)^2 = 16π, that of circle Q is π(2)^2 = 4π, and that of circle R is π(1)^2 = π, The area of the shaded region is the difference between the areas of circle Q and circle R. Therefore the area of the shaded region is 4π - π = 3π, and hence 3π/(16π) = 3/16 of circle P is shaded.

Answer: A
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Where does the problem say the ratios between the 3 circles? How do you know that the ratios are 1:2:4?
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sushmitha2
Where does the problem say the ratios between the 3 circles? How do you know that the ratios are 1:2:4?


Hi sushmitha2

nowhere in problem statement explicitly said the ratio between circles.

But u have to deduce the ratio as info given in stem

consider any numerical value of radius of big or small circle.
u will then get the ratio as the dia of smaller circle is the radius of just bigger respective circle.

Hope it helps :)
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Bunuel: I saw the above solutions but could you please correct me where am I going wrong here?

Shaded portion = Area of Circle P - Area of Circle R
Shaded portion = pi*(PT)^2 - pi*(PT/4)^2
Shaded portion = 15/16*pi*(PT)^2
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If P, Q and R are the centers of circles P, Q, and R and the points P, Q, R and T all lie on the same line, what portion of circle P is shaded?

A. 3/16
B. 1/5
C. 6/25
D. 1/4
E. 3/8



Now, to solve this question, what I did was:

1.Take the Diameter of circle P as 2X , meaning the radius would be X.

2.Find the area of circle P : Pi * X^2

3. Observing the image we can see that point P to point T is the radius of circle P, meaning that the radius of circle P is the diameter of circle Q, making the radius X/2

4. Now same as before, find the area of circle Q (not P) : Pi * X^2 / 4

5.We can now observe again that the radius of circle Q is the diameter of circle R, meaning that the radius of circle R is X/4

6. Now again, we find the area of circle R (not Q) : Pi * X^2/ 16

7. To find the area of just the shaded bit, we do : Pi * X^2 /4 - Pi * X^2/ 16 = 3 * Pi * X^2 / 16

8. And finally, to find what proportion of circle P is shaded , we simply do Area of shaded part / Area of circle P


3 * Pi * X^2 / 16 Divided by Pi * X^2 = ( 3 * Pi * X^2 / 16 ) * (1 / Pi * X2) = 3/16

Answer = 3/16 = A
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