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If pqrst = 4, then is p = 1/q ?
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15 Jan 2015, 07:15
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44% (02:04) correct 56% (01:59) wrong based on 160 sessions
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If pqrst = 4, then is p = 1/q ? (1) r = s = t (2) Three of p, q, r, s, t are integers
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Re: If pqrst = 4, then is p = 1/q ?
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15 Jan 2015, 10:04
1) Case 1: r = s = t = 1 then pq = 4 Case 2: pq = 1 and r = s = t > rst=4 > r=2^2/3 Not sufficient 2) Not sufficient 1+2) since three of p, q, r, s, t are integers Case 2 cannot take place. Answer C.
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Re: If pqrst = 4, then is p = 1/q ?
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19 Jan 2015, 04:29
Bunuel wrote: If pqrst = 4, then is p = 1/q ?
(1) r = s = t
(2) Three of p, q, r, s, t are integers The correct answer is C.
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Re: If pqrst = 4, then is p = 1/q ?
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17 May 2016, 06:31
gmat6nplus1 wrote: 1) Case 1: r = s = t = 1 then pq = 4 Case 2: pq = 1 and r = s = t > rst=4 > r=2^2/3 Not sufficient
2) Not sufficient
1+2) since three of p, q, r, s, t are integers Case 2 cannot take place. Answer C. I guess you are referring to r as third root of 4, but it looks to be 4\3 so got a bit confused. Can you please explain this example further, not very clear.
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Re: If pqrst = 4, then is p = 1/q ?
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17 May 2016, 16:28
If we modify the original condition and the question, it is p=1/q?, 4/qrst=1/q?. If we divide each side with q, we get 4/rst=1?, rst=4?. There are 5 variables (p,q,r,s,t) and 1 equation (pqrst=4). In order to match the number of variables to the number of equations, we need 4 more equations. Since the condition 1) and the condition 2) each has 1 equation, we lack 2 equations. Hence, there is high chance that E is the correct answer. Using both the condition 1) and the condition 2), it states r=s=t are 3 integers, we get r=s=t=1, 1, 2, 2,...... However, in any case we cannot obtain rst=4. Hence, the answer is no and the conditions are sufficient. Therefore, the answer is C.  For cases where we need 3 more equations, such as original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 80% chance that E is the answer (especially about 90% of 2 by 2 questions where there are more than 3 variables), while C has 15% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since E is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, C or D.
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Re: If pqrst = 4, then is p = 1/q ?
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23 Jun 2016, 08:05
Bunuel wrote: If pqrst = 4, then is p = 1/q ?
(1) r = s = t
(2) Three of p, q, r, s, t are integers Bunuel chetan2uCan someone please provide a detailed answer? I've been trying to wrap my head around this. I understand that individual statements are insufficient to answer the question. However, even using both statements it is quite possible that p could be or could not be equal to 1/q. We know that r = s = t and all three of them are integers. So, r, s, and t could be positive/negative integers. Let's say r = s = t = 1 => rst = 1 => pq = 4. To satisfy this equation, p and q can take any of the following values: p = 4, q = 1/4 (or vice versa) => pq = 4 p = 8, q = 1/2 (or vice versa) => pq = 4 p = 16, q = 1/4 (or vice versa) => pq = 4 etc. Let's say r = s = t = 2 => rst = 8 => pq = 1/2. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. Let's say r = s = t = 2 => rst = 8 => pq = 1/2. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. Let's say r = s = t = 1 => rst = 1 => pq = 4. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. We are not given any information about p or q. So, the answer should be (E) not (C), right? Please let me know what am I missing here. Thanks.



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Re: If pqrst = 4, then is p = 1/q ?
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23 Jun 2016, 08:20
jayshah0621 wrote: Bunuel wrote: If pqrst = 4, then is p = 1/q ?
(1) r = s = t
(2) Three of p, q, r, s, t are integers Bunuel chetan2uCan someone please provide a detailed answer? I've been trying to wrap my head around this. I understand that individual statements are insufficient to answer the question. However, even using both statements it is quite possible that p could be or could not be equal to 1/q. We know that r = s = t and all three of them are integers. So, r, s, and t could be positive/negative integers. Let's say r = s = t = 1 => rst = 1 => pq = 4. To satisfy this equation, p and q can take any of the following values: p = 4, q = 1/4 (or vice versa) => pq = 4 p = 8, q = 1/2 (or vice versa) => pq = 4 p = 16, q = 1/4 (or vice versa) => pq = 4 etc. Let's say r = s = t = 2 => rst = 8 => pq = 1/2. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. Let's say r = s = t = 2 => rst = 8 => pq = 1/2. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. Let's say r = s = t = 1 => rst = 1 => pq = 4. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. We are not given any information about p or q. So, the answer should be (E) not (C), right? Please let me know what am I missing here. Thanks. Notice that if p = 1/q, then pq = q*1/q = 1. In neither of your examples pq is 1. So, even you have a definite NO answer to the question.
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Re: If pqrst = 4, then is p = 1/q ?
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23 Jun 2016, 08:31
Bunuel wrote: jayshah0621 wrote: Bunuel wrote: If pqrst = 4, then is p = 1/q ?
(1) r = s = t
(2) Three of p, q, r, s, t are integers Bunuel chetan2uCan someone please provide a detailed answer? I've been trying to wrap my head around this. I understand that individual statements are insufficient to answer the question. However, even using both statements it is quite possible that p could be or could not be equal to 1/q. We know that r = s = t and all three of them are integers. So, r, s, and t could be positive/negative integers. Let's say r = s = t = 1 => rst = 1 => pq = 4. To satisfy this equation, p and q can take any of the following values: p = 4, q = 1/4 (or vice versa) => pq = 4 p = 8, q = 1/2 (or vice versa) => pq = 4 p = 16, q = 1/4 (or vice versa) => pq = 4 etc. Let's say r = s = t = 2 => rst = 8 => pq = 1/2. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. Let's say r = s = t = 2 => rst = 8 => pq = 1/2. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. Let's say r = s = t = 1 => rst = 1 => pq = 4. Again, to satisfy this equation, it is not necessary that p must be equal to 1/q. We are not given any information about p or q. So, the answer should be (E) not (C), right? Please let me know what am I missing here. Thanks. Notice that if p = 1/q, then pq = q*1/q = 1. In neither of your examples pq is 1. So, even you have a definite NO answer to the question. Uh oh. Silly me Thanks for the explanation! Kudos!



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Re: If pqrst = 4, then is p = 1/q ?
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23 Jun 2016, 19:16
gauz wrote: gmat6nplus1 wrote: 1) Case 1: r = s = t = 1 then pq = 4 Case 2: pq = 1 and r = s = t > rst=4 > r=2^2/3 Not sufficient
2) Not sufficient
1+2) since three of p, q, r, s, t are integers Case 2 cannot take place. Answer C. I guess you are referring to r as third root of 4, but it looks to be 4\3 so got a bit confused. Can you please explain this example further, not very clear. ^Figured it out, i might be high when posting this doubt
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Re: If pqrst = 4, then is p = 1/q ?
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13 Sep 2018, 11:46
Is p = 1/q > Is pq = 1 > Is rst = 4 ? (1) r = s = t . If r = s = t = 1 > No, If r = s = t = \(\sqrt[3]{4}\) > Yes. > Not sufficient. (2) Three of p, q, r, s, t are integers. If r, s, t are integers > No. If r, s, t are not integers at the same time, then Yes (i.e. r=1, s=3, t=4/3) or No (i.e. r=1, s=3, r=2/3). > Not sufficient. (1) + (2): {p, q, r, s, t} = {p, q, r, r, r} > p, q, r are integers > All 5 variables p, q, r, s, t are integer. > \(rst\neq{4}\) > No. > Sufficient. Answer C. Bunuel wrote: If pqrst = 4, then is p = 1/q ?
(1) r = s = t
(2) Three of p, q, r, s, t are integers
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Re: If pqrst = 4, then is p = 1/q ?
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