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q = 3 * [3^(1/2)] r = 1 + 2[3^(1/2)] s = 3 + [3^(1/2)]
14. If q, r and s are the numbers shown above, which of the following shows their order from greatest to least? (A) q, r, s (B) q, s, r (C) r, q, s (D) s, q, r (E) s, r, q
is there a shortcut to this question besides substituting 1.7 into each equation and working it out?
Re: q = 3 * r = 1 + 2 s = 3 + 14. If q, r and s are the
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27 Jan 2014, 12:44
2
bmwhype2 wrote:
q = 3 * [3^(1/2)] r = 1 + 2[3^(1/2)] s = 3 + [3^(1/2)]
14. If q, r and s are the numbers shown above, which of the following shows their order from greatest to least? (A) q, r, s (B) q, s, r (C) r, q, s (D) s, q, r (E) s, r, q
is there a shortcut to this question besides substituting 1.7 into each equation and working it out?
Haha, I don't know about tedious. Honestly, it only took me about 10 seconds to operate by 1.7 for all answer choices. I think that knowing that sqrt (3) = 1.7 and sqrt (2) = 1.4 approximately is a great shortcut in many problems. I think it is the fastest approach for this one
If q, r and s are the numbers shown above, which of the following show
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14 Jun 2018, 06:25
sarasjain20 wrote:
q=3\sqrt{3} r=1+2\sqrt{3} s=3+\sqrt{3}
14. If q, r and s are the numbers shown above, which of the following shows their order from greatest to least? (A) q, r, s (B) q, s, r (C) r, q, s (D) s, q, r (E) s, r, q
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The best way forward in the question is the approximation
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68% (01:15) correct 
