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# If r*s≠0, then what is the value of r/s + s/r? (1) r*s=8 (2) r/s=2

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Joined: 26 Dec 2018
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Location: India
If r*s≠0, then what is the value of r/s + s/r? (1) r*s=8 (2) r/s=2  [#permalink]

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Updated on: 07 Jan 2019, 02:05
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If r*s≠0, then what is the value of r/s + s/r?

(1) r*s=8

(2) r/s=2

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Originally posted by UB001 on 06 Jan 2019, 21:55.
Last edited by Bunuel on 07 Jan 2019, 02:05, edited 1 time in total.
Edited the question.
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WE: Engineering (Energy and Utilities)
Re: If r*s≠0, then what is the value of r/s + s/r? (1) r*s=8 (2) r/s=2  [#permalink]

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06 Jan 2019, 22:02
Statement 1 is clearly insufficient.

Statement 2 gives r/s = 2, then s/r = 1/2
Therefore, r/s+s/r = 3/2

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Re: If r*s≠0, then what is the value of r/s + s/r? (1) r*s=8 (2) r/s=2  [#permalink]

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06 Jan 2019, 22:40
UB001 wrote:
If r•s≠0, then what is the value of r/s + s/r?

(1) r•s=8

(2) r/s=2

Statement (1)
r•s=8, can be 4*2 = 8 or 6+2=8, as •, is not defined, this will give multiple values for the question

Statement (2)
r/s = 2, when substituted in r/s + s/r, will give only one solution, Thereby sufficient by itself.

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Re: If r*s≠0, then what is the value of r/s + s/r? (1) r*s=8 (2) r/s=2   [#permalink] 06 Jan 2019, 22:40
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