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caro2789
Joined: 05 Jul 2013
Last visit: 13 Mar 2014
Posts: 6
Given Kudos: 3
Location: Germany
Schools: Insead '14 (A) HBS '17 HKUST '17 CBS '16 (D)
GMAT 1: 640 Q38 V39
GMAT 2: 700 Q47 V39
GPA: 3.4
WE:Investment Banking (Real Estate)
06 Sep 2013, 03:39
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
74% (01:26) correct
26%
(01:33)
wrong
based on 798
sessions
History
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If Susan takes 9 seconds to run y yards, how many minutes will it take her to run x yards at the same rate?
A) \(\frac{xy}{9}\)
B) \(\frac{9x}{60y}\)
C) \(\frac{60xy}{9}\)
D) \(\frac{xy}{540}\)
E) \(\frac{540x}{y}\)
A) \(\frac{xy}{9}\)
B) \(\frac{9x}{60y}\)
C) \(\frac{60xy}{9}\)
D) \(\frac{xy}{540}\)
E) \(\frac{540x}{y}\)
06 Sep 2013, 03:44
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caro2789
Rate*Time=Distance.
Since, Susan takes 9 seconds to run \(y\) yards, then her rate is \(Rate=\frac{Distance}{Time}=\frac{y}{9}\) yards per second.
To run \(x\) yards at this rate she'll need \(Time=\frac{Distance}{Rate}=\frac{x}{(\frac{y}{9})}=\frac{9x}{y}\) seconds, which is \(\frac{9x}{60y}\) minutes.
Answer: B.
P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Please pay attention to the rule #3. Thank you.
General Discussion
09 Sep 2013, 09:27
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Susan runs y yards in 9 seconds which means her rate over that particular distance is: r = y/9
We're told to look for how long it will take her to run x yards at the same rate (i.e. r=y/9)
Time taken:
t = d/r
t = x/r
t = x/(y/9)
t = 9x/y
This gives us the time in seconds but we need to multiply by 60 (seconds) to get the time in minutes.
t = 9x/60y
I had a bit of trouble conceptualizing this problem at first, specifically why we would find the time of the new distance (in minutes) by dividing by the old rate. Well, I guess it was a silly problem to be caught up on. All we want to know is how long (t) it will take for x yards to be covered at the same rate we determined to be (y/9) Then, we just had to multiply by 60 seconds to get y in terms of minutes. I guess the final answer tripped me up because of the way it multiplied out (in other words, if t = d/r then why is d here equal to 9 seconds*x distance.) I'm not sure what I can do to help me better understand these kinds of problems.
ANSWER: b.) 9x/60y
P.S. Bunuel, I believe you got the correct answer (it's the same one I got) but you marked down the incorrect answer choice.
Cheers!
We're told to look for how long it will take her to run x yards at the same rate (i.e. r=y/9)
Time taken:
t = d/r
t = x/r
t = x/(y/9)
t = 9x/y
This gives us the time in seconds but we need to multiply by 60 (seconds) to get the time in minutes.
t = 9x/60y
I had a bit of trouble conceptualizing this problem at first, specifically why we would find the time of the new distance (in minutes) by dividing by the old rate. Well, I guess it was a silly problem to be caught up on. All we want to know is how long (t) it will take for x yards to be covered at the same rate we determined to be (y/9) Then, we just had to multiply by 60 seconds to get y in terms of minutes. I guess the final answer tripped me up because of the way it multiplied out (in other words, if t = d/r then why is d here equal to 9 seconds*x distance.) I'm not sure what I can do to help me better understand these kinds of problems.
ANSWER: b.) 9x/60y
P.S. Bunuel, I believe you got the correct answer (it's the same one I got) but you marked down the incorrect answer choice.
Cheers!
