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If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N

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If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 14 Oct 2015, 20:22
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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 14 Oct 2015, 20:35
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3+15+32+N+1= 18 x 4 = 72
=>N +51 = 72
=>N=21
Answer C
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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 14 Oct 2015, 20:45
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Bunuel wrote:
If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18, then N =

(A) 19
(B) 20
(C) 21
(D) 22
(E) 29


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The average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18
So, (sum of all 4 numbers)/4 = 18
Multiply both sides by 4 to get: sum of all 4 numbers = 72
This means that 3 + 15 + 32 + (N+1) = 72
Simplify: N + 51 = 72
Solve to get: N = 21

Answer: C
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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 08 May 2016, 05:35
(3+15+32+N+1)/4=18
51+N=18*4
N=72-51
N=21

Is this approach correct?
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If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 08 May 2016, 05:38
paidlukkha wrote:
(3+15+32+N+1)/4=18
51+N=18*4
N=72-51
N=21

Is this approach correct?


Total of 4 numbers is 14*8 = 72

Total of 3 numbers is 50 (3+15+32)

So, N+1 = 22

Or N = 21
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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 08 May 2016, 07:45
3+15+32+N+1/4= 18

N= 18*4 - 51= 21
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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 09 Dec 2016, 01:09
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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 10 Dec 2016, 00:39
Bunuel wrote:
If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18, then N =

(A) 19
(B) 20
(C) 21
(D) 22
(E) 29


Kudos for a correct solution.


3 + 15 + 32 + ( N + 1 ) = 72

Or, N + 51 = 72

So, N = 21

Hence, answer will be (C) 21

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Abhishek....

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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

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New post 18 Aug 2018, 21:01
To answer this, we need to find the sum of the 4 numbers which equals 51+N

we know that average x no. of numbers = sum hence 18 * 4= 51+ N, solving which gives us N=21
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Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N &nbs [#permalink] 18 Aug 2018, 21:01
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