GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 May 2019, 15:47

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 55188
If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

14 Oct 2015, 21:22
6
7
00:00

Difficulty:

5% (low)

Question Stats:

90% (00:54) correct 10% (01:03) wrong based on 1089 sessions

### HideShow timer Statistics

If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18, then N =

(A) 19
(B) 20
(C) 21
(D) 22
(E) 29

Kudos for a correct solution.

_________________
Verbal Forum Moderator
Status: Greatness begins beyond your comfort zone
Joined: 08 Dec 2013
Posts: 2289
Location: India
Concentration: General Management, Strategy
Schools: Kelley '20, ISB '19
GPA: 3.2
WE: Information Technology (Consulting)
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

14 Oct 2015, 21:35
1
3+15+32+N+1= 18 x 4 = 72
=>N +51 = 72
=>N=21
_________________
When everything seems to be going against you, remember that the airplane takes off against the wind, not with it. - Henry Ford
The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long
+1 Kudos if you find this post helpful
CEO
Joined: 12 Sep 2015
Posts: 3717
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

14 Oct 2015, 21:45
1
Bunuel wrote:
If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18, then N =

(A) 19
(B) 20
(C) 21
(D) 22
(E) 29

Kudos for a correct solution.

The average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18
So, (sum of all 4 numbers)/4 = 18
Multiply both sides by 4 to get: sum of all 4 numbers = 72
This means that 3 + 15 + 32 + (N+1) = 72
Simplify: N + 51 = 72
Solve to get: N = 21

_________________
Test confidently with gmatprepnow.com
Senior Manager
Joined: 11 Nov 2014
Posts: 326
Location: India
WE: Project Management (Telecommunications)
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

08 May 2016, 06:35
(3+15+32+N+1)/4=18
51+N=18*4
N=72-51
N=21

Is this approach correct?
Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4469
Location: India
GPA: 3.5
If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

08 May 2016, 06:38
paidlukkha wrote:
(3+15+32+N+1)/4=18
51+N=18*4
N=72-51
N=21

Is this approach correct?

Total of 4 numbers is 14*8 = 72

Total of 3 numbers is 50 (3+15+32)

So, N+1 = 22

Or N = 21
_________________
Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )
Current Student
Joined: 18 Oct 2014
Posts: 835
Location: United States
GMAT 1: 660 Q49 V31
GPA: 3.98
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

08 May 2016, 08:45
1
3+15+32+N+1/4= 18

N= 18*4 - 51= 21
_________________
I welcome critical analysis of my post!! That will help me reach 700+
Current Student
Joined: 12 Aug 2015
Posts: 2616
Schools: Boston U '20 (M)
GRE 1: Q169 V154
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

09 Dec 2016, 02:09
1
Here is my solution to this one-->

Suing the concept of mean =>

$$Mean =\frac{Sum}{#}$$

$$\frac{51+n}{4}=18$$
Hene n=72-51 = 21
Hence C

_________________
Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4469
Location: India
GPA: 3.5
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

10 Dec 2016, 01:39
Bunuel wrote:
If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N + 1) is 18, then N =

(A) 19
(B) 20
(C) 21
(D) 22
(E) 29

Kudos for a correct solution.

3 + 15 + 32 + ( N + 1 ) = 72

Or, N + 51 = 72

So, N = 21

Hence, answer will be (C) 21

_________________
Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )
Intern
Joined: 19 May 2016
Posts: 23
Location: Pakistan
Concentration: Marketing, Strategy
GPA: 3.1
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N  [#permalink]

### Show Tags

18 Aug 2018, 22:01
To answer this, we need to find the sum of the 4 numbers which equals 51+N

we know that average x no. of numbers = sum hence 18 * 4= 51+ N, solving which gives us N=21
Re: If the average (arithmetic mean) of the four numbers 3, 15, 32, and (N   [#permalink] 18 Aug 2018, 22:01
Display posts from previous: Sort by