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If the length and width of rectangle A are 10 percent less and 30 perc

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If the length and width of rectangle A are 10 percent less and 30 perc [#permalink]

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New post 27 Sep 2017, 03:50
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If the length and width of rectangle A are 10 percent less and 30 percent less respectively than the length and width of rectangle B, the area of A is equal to what percent of the area of B?

(A) 63%
(B) 60%
(C) 40%
(D) 6%
(E) 3%
[Reveal] Spoiler: OA

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Re: If the length and width of rectangle A are 10 percent less and 30 perc [#permalink]

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New post 27 Sep 2017, 05:44
Let length and width of the rectangle B are X and Y .

So area of rectangle B is XY.

From given data we get length and rectangle of rectangle A are 0.9X and 0.7Y

So area of rectangke A is 0.63XY

Percentage of Area of rectangle A / Area of rectangle B = (0.63XY/XY )*100 = 63%

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Re: If the length and width of rectangle A are 10 percent less and 30 perc [#permalink]

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New post 27 Sep 2017, 09:34
If the length and width of rectangle A are 10 percent less and 30 percent less respectively than the length and width of rectangle B, the area of A is equal to what percent of the area of B?

Let measurement of rectangle B = l*b

Measurement of A => 10% less of l and 30% less of b = 0.9l & 0.7b

Area of A = 0.9l * 0.7b = 0.63 l*b = 0.63 * Area of B
=> Area of A is 63 % of area of B

Answer: A

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Re: If the length and width of rectangle A are 10 percent less and 30 perc [#permalink]

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New post 27 Sep 2017, 09:37
Bunuel wrote:
If the length and width of rectangle A are 10 percent less and 30 percent less respectively than the length and width of rectangle B, the area of A is equal to what percent of the area of B?

(A) 63%
(B) 60%
(C) 40%
(D) 6%
(E) 3%


As nothing is mentioned about the sides we can assume that length and breadth of the rectangle B be \(100\) & \(100\) respectively

so rectangle A's length and breadth will be \(90\) & \(70\)

Hence % area of A \(= (\frac{90*70}{100*100})*100 = 63%\)

Option A

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Re: If the length and width of rectangle A are 10 percent less and 30 perc [#permalink]

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New post 01 Oct 2017, 11:11
Bunuel wrote:
If the length and width of rectangle A are 10 percent less and 30 percent less respectively than the length and width of rectangle B, the area of A is equal to what percent of the area of B?

(A) 63%
(B) 60%
(C) 40%
(D) 6%
(E) 3%


We can let L = the length of rectangle B and W = the width of rectangle B. Thus, the area of rectangle B is LW and the area of rectangle A is (0.9L)(0.7W) = 0.63LW.

So, the area of rectangle A is 63% of the area of rectangle B.

Answer: A
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Kudos [?]: 991 [0], given: 5

Re: If the length and width of rectangle A are 10 percent less and 30 perc   [#permalink] 01 Oct 2017, 11:11
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