sarb wrote:

If the number x3458623y is divisible by 88, what is the value of x?

A. 1

B. 2

C. 3

D. 4

E. 5

x3458623y is divisible by 88 so, it should be divisible by 8 and 11

x+14+y -17 = n * 11

x+y-3 = n*11

n cant be 2, as in that case RHS will become 22, and on LHS the max we can get is 9+9-3 = 15

so n=0 or 1

now it should be divisible by 8 also, so 23y should be divisible by 8

240 is perfectly divisible by 8, so the no less then that will be 232

thus, y=2

now, x+2-3 =n*11

x-1=n*11

now n=1 is also not possible as lhs max can only be 9-1 =8

thus, n=0

hence, x=1

Ans: A

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