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21 May 2017, 12:32
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If the ratio of two numbers is 6 and their sum is 21, what is the value of the larger number?
(A) 1
(B) 5
(C) 12
(D) 17
(E) 18
(A) 1
(B) 5
(C) 12
(D) 17
(E) 18
21 May 2017, 13:20
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Let the two no: be x and y therefore ratio of two numbers is x/y =6 ---->(1)
and
x+y = 21 ---->(2)
From (1) and (2) we get,
6y+y = 21 ----> y=3 therefore x = 18
Hence the answer is option E.
and
x+y = 21 ---->(2)
From (1) and (2) we get,
6y+y = 21 ----> y=3 therefore x = 18
Hence the answer is option E.
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21 May 2017, 18:10
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Bunuel
If the ratio of two numbers is 6 and their sum is 21, what is the value of the larger number?
(A) 1
(B) 5
(C) 12
(D) 17
(E) 18
(A) 1
(B) 5
(C) 12
(D) 17
(E) 18
Let the two numbers be a and b.
Ratio of a to b => \(\frac{a}{b}\) = 6 -------------(i)
Sum of a and b => a + b = 21
a = 21 - b --------------------(ii)
Substituting a in equation (i)
\(\frac{21 - b}{b}\) = 6
21 - b = 6b
7b = 21
b = 3
a = 21 - b = 21 - 3 = 18
Therefore value of the larger number = 18
Answer E...
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