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# If x≠2, then [3x^2(x-2)-x+2]/(x-2)=

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21 Nov 2003, 13:06
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Question Stats:

76% (01:50) correct 24% (01:28) wrong based on 213 sessions

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If x≠2, then $$\frac{3x^2(x-2)-x+2}{(x-2)}=$$

(A) 3x^2-x+2
(B) 3x^2+1
(C) 3x^2
(D) 3x^2-1
(E) 3x^2-2

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-x-2-then-x-110471.html
[Reveal] Spoiler: OA

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shubhangi

Last edited by Bunuel on 19 May 2015, 05:45, edited 2 times in total.
Renamed the topic, edited the question and added the OA.
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:27
it this ques. correct?
or, is it like: 3x^2 (x-2) -x + 2/(x-2) ...?

either way, the solution doesn't give a real solution to the equation.
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:30
I know ..it is bit confusing..well but it is thta way only...
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shubhangi

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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:31
I think the correct equation is: (3x^2 (x-2) - x + 2)/(x - 2)

And the answer is 3x^2 - 1.
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:32
if wonder_gmat is right, then the solution is right
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:36
can u show me the working pls.
The answer is right.. problem in printing..
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shubhangi

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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:42
(3x┬▓(x - 2) - x + 2) / (x - 2)
= (3x┬▓(x - 2) - 1(x - 2)) / (x - 2)
= ((3x┬▓ - 1) (x - 2)) / (x - 2)
= 3x┬▓ - 1 ..... Quantity (x - 2) cancels out

shubhangi,
Could you copy the question right next time please? I ended up wasting time on this problem to make it work somehow until I looked it up in OG.
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:43
It wasnt my fault..anywyas, it is books priniting mistake..
Even i wasted my time to solve it.
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shubhangi

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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:50
shubhangi wrote:
It wasnt my fault..anywyas, it is books priniting mistake..
Even i wasted my time to solve it.

Umm... no it's not the book. Otherwise I wouldn't have been able to solve it after looking up in the book.
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 13:53
What do u mean?? that problme is still in front of me.. and how could i be ignoring that bracket.. its only book mistake..but not mine.
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shubhangi

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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 14:01
guyz..guyz.. calm down. no...

it's good that we got a wrong ques.
atleast, this keeps the gears--in mind--running. easy problems don't help you much in becoming logical
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 14:39
dj wrote:
guyz..guyz.. calm down. no...

it's good that we got a wrong ques.
atleast, this keeps the gears--in mind--running. easy problems don't help you much in becoming logical

don't worry dj, we're not arguing. Well at least I am not. Supposed I am friends with shubhangi HAHA...
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 15:13
Exactly...i dont think we are fighting.. we are just giving our own explanations i guess......atleast i am...
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shubhangi

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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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21 Nov 2003, 15:39
don't scare me...

kiddin'
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Re: If x≠2, then [3x^2(x-2)-x+2]/(x-2)= [#permalink]

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19 May 2015, 02:49
its from 1000 gmat....
and still no solution...
i think Chinese people are making these kinda questions for taking our moral down.....

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kinaare paaon phailane lage hian,
nadi se roz mitti kat rahi hai....

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19 May 2015, 05:46
Expert's post
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shubhangi wrote:
If x≠2, then $$\frac{3x^2(x-2)-x+2}{(x-2)}=$$

(A) 3x^2-x+2
(B) 3x^2+1
(C) 3x^2
(D) 3x^2-1
(E) 3x^2-2

$$\frac{3x^2(x-2)-x+2}{(x-2)}=\frac{3x^2(x-2)-(x-2)}{(x-2)}=\frac{(x-2)(3x^2-1)}{(x-2)}=3x^2-1$$.

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-x-2-then-x-110471.html
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If x≠2, then [3x^2(x-2)-x+2]/(x-2)=   [#permalink] 19 May 2015, 05:46
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