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If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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06 Mar 2014, 03:03
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The Official Guide For GMAT® Quantitative Review, 2ND EditionIf \(x \neq 2\), then \(\frac{3x^2(x2)x+2}{x2}\) (A) 3x^2  x + 2 (B) 3x^2 + 1 (C) 3x^2 (D) 3x^2  1 (E) 3x^2  2 Problem Solving Question: 133 Category: Algebra Simplifying algebraic expressions Page: 79 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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06 Mar 2014, 03:03



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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06 Mar 2014, 03:08
Factor out (x2) which would get cancelled with the denominator, leaving us with 3x^2  1.
Answer (D).



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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06 Mar 2014, 04:05
If x#2, then \(\frac{3x^2(x2)x+2}{x2}\) (A) 3x^2  x + 2 (B) 3x^2 + 1 (C) 3x^2 (D) 3x^2  1 (E) 3x^2  2 Sol: The Given expression can be rewritten as {3x^2 (x2) 1 (x2)}/(x2) Or Taking (x2) common in the numerator we get ({3x^21)(x2)}/(x2) Cancelling out (x2), we get 3x^21 Ans is D
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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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06 Mar 2014, 19:54
(D) \(3x^2  1\) Only one step required to get the answer: Rewrite equation as \(\frac{3x^2(x2)  1(x2)}{(x2)}\) = \(\frac{(3x^21) (x2)}{(x2)}\) = \(3x^21\)
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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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08 Mar 2014, 12:50



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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14 Mar 2014, 04:35
Pick Numbers:
x = 4
3*4² (42)4+2 / 4  2 = ...solve = 47, 47 = 3*4²1. Hence D.



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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02 Mar 2015, 13:29
PareshGmat wrote: (D) \(3x^2  1\)
Only one step required to get the answer: Rewrite equation as
\(\frac{3x^2(x2)  1(x2)}{(x2)}\)
= \(\frac{(3x^21) (x2)}{(x2)}\)
= \(3x^21\) Where does the "1" come from, why isnt it 3x^2(x2)  x + 2 / x  2 > remove x 2 in the denominator and you get 3x^2  x + 2?



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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02 Mar 2015, 14:46
Hi erikvm, The GMAT will frequently test you on rules that you know, but in ways that you're not used to thinking about.... Consider these examples: Can you simplify 4X/4? What 'step' do you do? Next, can you simplify (4X + 6)/2? What 'steps' do you do here? The same rules apply to the question here. You have to divide the ENTIRE numerator by the denominator. As it stands, this question can be solved rather easily by TESTing VALUES. Try using X = 3 and see how long it takes to get to the correct answer.... GMAT assassins aren't born, they're made, Rich
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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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03 Mar 2015, 04:20
Thanks Rich, you always manage to explain things in a very simple way.



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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21 Feb 2016, 14:15
Hi Abhinav, You CAN get to the correct answer by TESTing VALUES and using X=1. However, I think that you made a mistake in your calculation at some point. Answer B does NOT match up with the value of that equation when you use X=1. GMAT assassins aren't born, they're made, Rich
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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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15 Mar 2016, 14:14
I don't get why you distribute the "" into the "2" with no parentheses around the last two terms. I can understand distributing if it read "(x+2)" but it reads "x+2." Am I losing my mind?



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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15 Mar 2016, 23:52



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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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27 Apr 2017, 21:35
This question seems easy (I got it wrong btw), but it's tricky if you don't see the "1", so I will write it all out here for those who are struggling to see it. \(\cfrac { 3{ x }^{ 2 }(x2)x+2 }{ x2 } \\ \cfrac { 3{ x }^{ 2 }(x2)1(x2) }{ x2 } \\ \cfrac { (x2)3{ x }^{ 2 }1 }{ x2 } \\ { 3x }^{ 2 }1\) OA
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Re: If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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29 May 2017, 21:57
Bunuel wrote: The Official Guide For GMAT® Quantitative Review, 2ND EditionIf \(x \neq 2\), then \(\frac{3x^2(x2)x+2}{x2}\) (A) 3x^2  x + 2 (B) 3x^2 + 1 (C) 3x^2 (D) 3x^2  1 (E) 3x^2  2 Problem Solving Question: 133 Category: Algebra Simplifying algebraic expressions Page: 79 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you! First realize that x2 appears in all three terms, albeit in an unfamiliar format in x+2 To convert x+2 to x2, pull out the 1 from both x and 2: 1*(x2). Now the 1 already appears in the bar, so you can just put x2 in parentheses to indicate that the 1 should be distributed. 3x^2*(x2) (x2)/(x2) Divide out x2 from all terms 3x^2  1.



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If x#2, then (3x^2(x2)x+2)/(x2)= [#permalink]
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10 Mar 2018, 06:42
Bunuel wrote: SOLUTION
If x#2, then \(\frac{3x^2(x2)x+2}{x2}\)
(A) 3x^2  x + 2 (B) 3x^2 + 1 (C) 3x^2 (D) 3x^2  1 (E) 3x^2  2
\(\frac{3x^2(x2)x+2}{x2}\);
\(\frac{3x^2(x2)(x2)}{x2}\);
Reduce by x2: \(3x^2  1\).
Answer: D. \(\frac{3x^2(x2)x+2}{x2}\) \(\frac{3x^2  x^2+2x+2}{x2}\) I get this by multiplying x by (x2) \(3x^2x+2x\) \(3x^2+x\) so where am i wrong ?




If x#2, then (3x^2(x2)x+2)/(x2)=
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