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If x >= 2400, then the value of 2x/(4x + 24) is approximately

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If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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New post Updated on: 31 Mar 2018, 10:20
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If \(x\geq {2400}\), then the value of \(\frac{2x}{4x + 24}\) is approximately

A. \(\frac{1}{7}\)

B. \(\frac{2}{7}\)

C. \(\frac{1}{2}\)

D. \(\frac{3}{5}\)

E. \(\frac{3}{2}\)

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Originally posted by AkshdeepS on 31 Mar 2018, 10:17.
Last edited by Bunuel on 31 Mar 2018, 10:20, edited 1 time in total.
Renamed the topic and edited the question.
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Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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New post 31 Mar 2018, 10:28
QZ wrote:
If \(x\geq {2400}\), then the value of \(\frac{2x}{4x + 24}\) is approximately

A. \(\frac{1}{7}\)

B. \(\frac{2}{7}\)

C. \(\frac{1}{2}\)

D. \(\frac{3}{5}\)

E. \(\frac{3}{2}\)


Since x is large enough then 24 is negligible in this case, thus \(\frac{2x}{4x + 24}\) will be very close to \(\frac{2x}{4x}=\frac{1}{2}\).

Answer: C.

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Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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New post 31 Mar 2018, 10:34
QZ wrote:
If \(x\geq {2400}\), then the value of \(\frac{2x}{4x + 24}\) is approximately

A. \(\frac{1}{7}\)

B. \(\frac{2}{7}\)

C. \(\frac{1}{2}\)

D. \(\frac{3}{5}\)

E. \(\frac{3}{2}\)


2x/(4x+24) simplifying it x/(2x+12)

since x is greater than 2400 . 2x will be much bigger value compare to 12
We can neglect 12 . So new eq-> x/2x=1/2

option c
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Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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New post 01 Apr 2018, 05:49
QZ wrote:
If \(x\geq {2400}\), then the value of \(\frac{2x}{4x + 24}\) is approximately

A. \(\frac{1}{7}\)

B. \(\frac{2}{7}\)

C. \(\frac{1}{2}\)

D. \(\frac{3}{5}\)

E. \(\frac{3}{2}\)


Plug in 2400 in the equation

\(\frac{2x}{4x + 24}\) = \(\frac{200}{401}\)

It is almost 1/2

Answer: C
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Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately &nbs [#permalink] 01 Apr 2018, 05:49
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If x >= 2400, then the value of 2x/(4x + 24) is approximately

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