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# If x >= 2400, then the value of 2x/(4x + 24) is approximately

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If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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Updated on: 31 Mar 2018, 10:20
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Difficulty:

15% (low)

Question Stats:

85% (01:21) correct 15% (01:52) wrong based on 51 sessions

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If $$x\geq {2400}$$, then the value of $$\frac{2x}{4x + 24}$$ is approximately

A. $$\frac{1}{7}$$

B. $$\frac{2}{7}$$

C. $$\frac{1}{2}$$

D. $$\frac{3}{5}$$

E. $$\frac{3}{2}$$

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Originally posted by AkshdeepS on 31 Mar 2018, 10:17.
Last edited by Bunuel on 31 Mar 2018, 10:20, edited 1 time in total.
Renamed the topic and edited the question.
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Posts: 50058
Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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31 Mar 2018, 10:28
QZ wrote:
If $$x\geq {2400}$$, then the value of $$\frac{2x}{4x + 24}$$ is approximately

A. $$\frac{1}{7}$$

B. $$\frac{2}{7}$$

C. $$\frac{1}{2}$$

D. $$\frac{3}{5}$$

E. $$\frac{3}{2}$$

Since x is large enough then 24 is negligible in this case, thus $$\frac{2x}{4x + 24}$$ will be very close to $$\frac{2x}{4x}=\frac{1}{2}$$.

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Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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31 Mar 2018, 10:34
QZ wrote:
If $$x\geq {2400}$$, then the value of $$\frac{2x}{4x + 24}$$ is approximately

A. $$\frac{1}{7}$$

B. $$\frac{2}{7}$$

C. $$\frac{1}{2}$$

D. $$\frac{3}{5}$$

E. $$\frac{3}{2}$$

2x/(4x+24) simplifying it x/(2x+12)

since x is greater than 2400 . 2x will be much bigger value compare to 12
We can neglect 12 . So new eq-> x/2x=1/2

option c
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Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately  [#permalink]

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01 Apr 2018, 05:49
QZ wrote:
If $$x\geq {2400}$$, then the value of $$\frac{2x}{4x + 24}$$ is approximately

A. $$\frac{1}{7}$$

B. $$\frac{2}{7}$$

C. $$\frac{1}{2}$$

D. $$\frac{3}{5}$$

E. $$\frac{3}{2}$$

Plug in 2400 in the equation

$$\frac{2x}{4x + 24}$$ = $$\frac{200}{401}$$

It is almost 1/2

Re: If x >= 2400, then the value of 2x/(4x + 24) is approximately &nbs [#permalink] 01 Apr 2018, 05:49
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