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If x and y are distinct non-negative integers, what is the value of x^y?
(1) y^x = 1
(2) (2^y)2^x = 1
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The question, along with OA, is flawed..
X and y are non negative integers so 0 or more..
1) \(y^x=1\) Possible when x is 0 and y could be anything...so x^y will be 0.. Also when y is 1 and X can be anything... So x^y will be equal to x . Insufficient
2) \((2^y)2^x=1=2^0.........y+x=0\)... Not possible... As both X and y are distinct so both cannot be 0 and none is negative, so no other combination will fit... FLAWED
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