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AbdurRakib
Joined: 11 May 2014
Last visit: 03 Mar 2026
Posts: 464
Given Kudos: 220
Status:I don't stop when I'm Tired,I stop when I'm done
Location: Bangladesh
Concentration: Finance, Leadership
Schools: Wharton '20 Yale '20 Tepper '20
GPA: 2.81
WE:Business Development (Real Estate)
22 Jul 2016, 12:34
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
65% (01:46) correct
35%
(01:52)
wrong
based on 693
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are distinct prime numbers, which of the following could be true?
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
A. \(\frac{x^y}{y}\) is an odd integer
B. \(x^2y^3=x^2\)
C. \(\frac{y^x}{4}\) is an even integer
D. \(\frac{xy}{2}\) is an even integer
E. \(x^y=y^x\)
22 Jul 2016, 13:06
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AbdurRakib
The keyword here is COULD.
Scanning the answer choices, I see that C could be true.
If x = 2 and y = 3, then (x^y)/4 = (2³)/4 = 2, and 2 IS an even integer.
Answer:
23 Jul 2016, 23:51
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AbdurRakib
Given, x and y are distinct Prime numbers.
A. \(\frac{x^y}{y}\) is an odd integer --> x and y doesn't have anything in common. So, the division would never be an Integer.Incorrect
B. \(x^2y^3\)=\(x^2\) --> it means y is 1 but i is not a prime number. Incorrect
C. \(\frac{y^x}{4}\) is an even integer --> For y=2 and X=3, we will have 8/4=2. An even Integer. Hence Correct Answer
D. \(\frac{xy}{2}\) is an even integer --> if xy/2 is integer, then one of x or y must be 2. which would mean it will cancel with the 2 at the denominator , hence it can never be Even. Incorrect
E. \(x^y\)=\(y^x\)[/quote] for two distinct primes, this property will never be true. Check for any set of pair. Incorrect
