chetan2u wrote:

Bunuel wrote:

If x and y are integers each with absolute value less than 5 and 7x - 6y = 3, how many values of x are there?

A. 1

B. 2

C. 3

D. 4

E. 5

Hi,

A way to do such Qs..

7x-6y=3...

7x=6y+3=3(2y+1)....

We can see from this that x HAS to be a multiple of 3..

Possible values are 3&-3..

But remember to check:-

if these values have y as an integer..

2y+1 can take any ODD values

And for X=3, y=3..

X=-3, y is -4..

So both are OK...

B

Hi

chetan2u, nice explanation, thank you.

Can you explain this part again if you don't mind?

**Quote:**

But remember to check:-

if these values have y as an integer..

2y+1 can take any ODD values

And for X=3, y=3..

X=-3, y is -4..

So both are OK...

and this

**Quote:**

We can see from this that x HAS to be a multiple of 3..

Possible values are 3&-3..

I've a sort of weakness with this type of questions :/ Any theory you can suggest in this regard?

_________________

Yours,

Siva Rama Krishna Meka