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For A+B to be even, A,b should either both be even or both should be odd.
As in our question, we have A as even, we want to find if B (3y) is odd or even.

Statement 1: Insufficient

Statement 2:
If x=0, then y can be odd or even.
Hence, the second statement is insufficient.

If we combine statement 1 and 2 then we get that -> as x^3 is odd -> x will be odd -> so x is not 0 -> y is odd -> 4x^4 + 3y will be odd.
Hence, answer is C.
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