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25 Oct 2018, 19:18
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
47% (02:36) correct
53%
(02:33)
wrong
based on 201
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are positive integers and y<5x, the remainder is z when 5x is divided by y. What is the value of z?
(1) When y+1 is divided by 5, the remainder is 1.
(2) When y+1 is divided by 4, the remainder is 2.
(1) When y+1 is divided by 5, the remainder is 1.
(2) When y+1 is divided by 4, the remainder is 2.
25 Oct 2018, 22:56
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Hi,
Answer has to be “E”.
There is not much information about “x”
Given:
x, y > 0 and integers
y < 5x
z = Rem When 5x is divided y.
Question: Value of “z”?
Statement I is insufficient:
When y+1 is divided by 5, the remainder is 1
i.e., y+1 could be 1,6, 11, 16, …..
So “y” values could be 0,5,10,15,20,25…(“y” can’t be zero as it is given y is positive).
Given y < 5x
Let’s say,
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
But if
x = 7 and y = 15
then “y” is still less than 15 < 35
But we get different z, i.e., z = 5
So different values of “z”. Not sufficient.
Statement II is insufficient.
When y+1 is divided by 4, the remainder is 2.
Similar to statement I,
y+1 could be 2,6, 10, 14,18 …..
So “y” values could be 1,5,9,13,17,21,25…(“y” can’t be zero as it is given y is positive).
Given y < 5x
Let’s say,
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
But if
x = 7 and y = 9
“y” is still less than 9 < 35
But z = 8
So different values of “z”. Not sufficient.
Together still insufficient:
Values could be still,
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
OR
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
x = 7 and y = 25
then “y” is less than 25 < 35
then z = 10
Still we are getting different values of “z”.
Together still not sufficient.
So the answer is E.
Hope this helps
Answer has to be “E”.
There is not much information about “x”
Given:
x, y > 0 and integers
y < 5x
z = Rem When 5x is divided y.
Question: Value of “z”?
Statement I is insufficient:
When y+1 is divided by 5, the remainder is 1
i.e., y+1 could be 1,6, 11, 16, …..
So “y” values could be 0,5,10,15,20,25…(“y” can’t be zero as it is given y is positive).
Given y < 5x
Let’s say,
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
But if
x = 7 and y = 15
then “y” is still less than 15 < 35
But we get different z, i.e., z = 5
So different values of “z”. Not sufficient.
Statement II is insufficient.
When y+1 is divided by 4, the remainder is 2.
Similar to statement I,
y+1 could be 2,6, 10, 14,18 …..
So “y” values could be 1,5,9,13,17,21,25…(“y” can’t be zero as it is given y is positive).
Given y < 5x
Let’s say,
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
But if
x = 7 and y = 9
“y” is still less than 9 < 35
But z = 8
So different values of “z”. Not sufficient.
Together still insufficient:
Values could be still,
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
OR
x = 7 and y = 5
then “y” is less than 5 < 35
then z = 0
x = 7 and y = 25
then “y” is less than 25 < 35
then z = 10
Still we are getting different values of “z”.
Together still not sufficient.
So the answer is E.
Hope this helps
Italiandrummer97
Joined: 17 Apr 2018
Last visit: 08 Sep 2020
Posts: 18
Given Kudos: 19
Location: Italy
Concentration: General Management, Entrepreneurship
Schools: HEC Sept19 intake (S)
GPA: 3.75
26 Oct 2018, 00:24
Kudos
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Jazzmin
We need to know:
A) The value of both y and 5x
Or
B)the value of the remainder.
No calculations needed, as in most DS questions.
POE:
1)No significant information given. Insufficient. Eliminate A and D.
2)Same as in 1. Insufficient. Eliminate B
1+2) We could be able to calculate the value of y, but we'd still be missing the value of 5x. Insufficient. Eliminate C.
Correct answer: E
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