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alphonsa
Joined: 22 Jul 2014
Last visit: 25 Oct 2020
Posts: 106
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Concentration: General Management, Finance
Schools: Cox '19 (D) Babson '19 (A$) Katz '19 (D) Eller"19 (A$) Northeastern '19 (A$) Krannert '19 (A$) ISB '18 (D) Rutgers '19 (A) Olin '19 (I)
GMAT 1: 670 Q48 V34
WE:Engineering (Energy)
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Schools: Cox '19 (D) Babson '19 (A$) Katz '19 (D) Eller"19 (A$) Northeastern '19 (A$) Krannert '19 (A$) ISB '18 (D) Rutgers '19 (A) Olin '19 (I)
GMAT 1: 670 Q48 V34
Posts: 106
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
61% (01:52) correct
39%
(01:58)
wrong
based on 142
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are positive integers, is x an even integer?
(1) x(y + 11) is an even integer.
(2) y^2 - 6y + 5 is an odd integer.
Source: 4gmat
(1) x(y + 11) is an even integer.
(2) y^2 - 6y + 5 is an odd integer.
Source: 4gmat
18 Aug 2014, 09:05
Kudos
Bookmarks
STAT1
If y is odd then X can be even or odd
If y is even then xis even
So, NOT SUFFICIENT
STAT2
(y-1)*(y-5)=odd
=> y = even
Doesn't talk about x so NOT SUFFICIENT
STAT1 and STAT2 Together
we know that y is even
=> y+11 is odd
=> x is even
So, SUFFICIENT
Answer will be C
Hope it helps!
If y is odd then X can be even or odd
If y is even then xis even
So, NOT SUFFICIENT
STAT2
(y-1)*(y-5)=odd
=> y = even
Doesn't talk about x so NOT SUFFICIENT
STAT1 and STAT2 Together
we know that y is even
=> y+11 is odd
=> x is even
So, SUFFICIENT
Answer will be C
Hope it helps!
18 Aug 2014, 09:41
Kudos
Bookmarks
If x and y are positive integers, is x an even integer?
(1) x(y + 11) is an even integer --> if y is an odd integer then y + 5 = even and x can be even as well as odd. Not sufficient.
(2) y^2 - 6y + 5 is an odd integer --> y^2 - 6y + 5 = y^2 - even + odd = y^2 + odd = odd --> y^2 = even --> y = even. No info about x. Not sufficient.
(1)+(2) Since from (2) y is even, then y + 11 = odd, thus for x(y + 11) = x*odd to be even, x must be even. Sufficient.
Answer: C.
(1) x(y + 11) is an even integer --> if y is an odd integer then y + 5 = even and x can be even as well as odd. Not sufficient.
(2) y^2 - 6y + 5 is an odd integer --> y^2 - 6y + 5 = y^2 - even + odd = y^2 + odd = odd --> y^2 = even --> y = even. No info about x. Not sufficient.
(1)+(2) Since from (2) y is even, then y + 11 = odd, thus for x(y + 11) = x*odd to be even, x must be even. Sufficient.
Answer: C.
