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If x and y are positive integers, is x divisible by 26 ?

Prime factorization of 26 = 2*13

(1) The least common multiple of x and y is 169
169 = \(13^2\)
So we know that 169 has 13 as a factor , but not 2. So this shows that x is not divisble by 26.

Option 1 Sufficient

(2) The greatest common factor of x and 39 is 13
X can be 13 or 26 or 169. We are not sure whether 2 is a factor of x.

Option 2 Insufficient

Ans A
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If x and y are positive integers, is x divisible by 26 ?

(1) The least common multiple of x and y is 169
(2) The greatest common factor of x and 39 is 13


is x divisible by 26 ? or 13*2 ?

(1) The least common multiple of x and y is 169

that means 169 is divisible by both x and y. 169 is a square of 13.
so x would be divisible by 13

but no mention of 2.
take y = 169
x could be 13, 169

sufficient

(2) The greatest common factor of x and 39 is 13

common factor as 13.. again means x could be 13 or multiple of 13.
no mention of 2.
x could be 13, 26, 42, 169*2, 169*4 etc..

Insufficient

Even after combining both. insufficient
IMCO (A)
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Hello from the GMAT Club BumpBot!

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