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If \(x \) and \(y\) are positive numbers, \(√x+√y=6\) and \(xy=4\), then what is the value of \(x+y\) ?

\(√x+√y=6\)
Square the both sides: \((√x+√y)^{2}=6^{2}\)
--> \(x+ y +2√(xy) = 36 \)

\(x+ y = 36 -2√(xy) = 36 -2√4= 36-4= 32\)

The answer is C.
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√x+√y=6
xy=4
square both sides
√x+√y=6
x+y+2√xy=36
x+y+2√4= 36
x+y+4=36
x+y=32
IMO C

If x and y are positive numbers, √x+√y=6 andxy=4, then what is the value of x+y ?

A. 2
B. 28
C. 32
D. 34
E. 36
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If x and y are positive numbers, √x+√y=6 and xy=4, then what is the value of x+y ?

A. 2
B. 28
C. 32
D. 34
E. 36

\((√x+√y)^2 = 6^2 \)
x + y + 2√x√y = 36
x + y = 36 - 2.√4
x + y = 36 - 4 = 32

Answer C.
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If x and y are positive numbers, √x+√y=6√x+√y=6 and xy=4xy=4, then what is the value of x+yx+y ?

A. 2
B. 28
C. 32
D. 34
E. 36

x + 2\sqrt{xy}+ y = 36
x + 2. 2 (for square root, we consider only the positive value) +y = 36
x + y = 32.

C is the answer
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(√x + √y)^2 = 36
x+2\(\sqrt{xy}\)+y = 36

substitute in xy = 4

x+ y + 4 = 36
x + y = 32

Answer: C
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Quote:
If x and y are positive numbers, √x+√y=6 and xy=4, then what is the value of x+y?

A. 2
B. 28
C. 32
D. 34
E. 36

√x+√y=6
(√x+√y)^2=6^2
x+y+2√xy=36
x+y=36-2(√4)
x+y=36-4=32

Ans (C)
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x + y = (√x+√y)^2 - 2√(xy) = 36 - 2√4 = 36 - 4 = 32

ANSWER IS (C)
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If x and y are positive numbers, √x+√y=6 and xy=4, then what is the value of x+y ?

A. 2
B. 28
C. 32
D. 34
E. 36

Given that,
√x+√y=6
(√x+√y)^2=6^2 ( Squaring to the both sides)
Or, x + 2√xy+ y = 36
Or, x + y + 2√xy = 36
Or, x + y + 2*2 = 36( Putting xy =4)
Or, x + y = 32

Answer: C(32)
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