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Bunuel
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X= C^ 18+b. IMO, E is the Answer
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(x-b)^1/3=c^6

[(x-b)^1/3]^3=(c^6)^3

x-b=c^18

E
x=c^18+b
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Bunuel
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
\(\sqrt[3]{x - b} = c^6\)

Or, \(x - b = c^{18}\)

Or, \(x = c^{18} + b\), Answer must be (E)
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Bunuel
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b

On cubing both the sides of the equation we get,
x-b= \(c^{18}\)
=> x=\(c^{18}\) +b

Therefore, the answer is option E.
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Bunuel
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
\(\sqrt[3]{x - b} = c^6\)

\(x - b = c^{18}\)

Or, \(b = c^{18} - b\), Answer must be (E)
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