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11 Oct 2019, 08:00
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If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?
A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
11 Oct 2019, 08:09
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On Cubing both the equations, we get
x-b = (c^6)^3 which can also be written as
x-b = (c^6)(c^6)(c^6) and hence we get x = (c^(6+6+6)) + b.
Therefore, E.
x-b = (c^6)^3 which can also be written as
x-b = (c^6)(c^6)(c^6) and hence we get x = (c^(6+6+6)) + b.
Therefore, E.
11 Oct 2019, 08:19
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Bunuel
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?
A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
x-b = c^18
x= c^18+b
IMO E
Posted from my mobile device
