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If (x - b)^(1/3) = c^6, then x = ?

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Bunuel
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If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   11 Oct 2019, 08:00
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If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
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E
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PrashantLakhotia
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If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   11 Oct 2019, 08:09
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On Cubing both the equations, we get
x-b = (c^6)^3 which can also be written as
x-b = (c^6)(c^6)(c^6) and hence we get x = (c^(6+6+6)) + b.
Therefore, E.
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Kinshook
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Re: If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   11 Oct 2019, 08:19
Bunuel wrote:
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b


x-b = c^18
x= c^18+b

IMO E

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Re: If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   11 Oct 2019, 18:57
X= C^ 18+b. IMO, E is the Answer
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Re: If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   11 Oct 2019, 22:27
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(x-b)^1/3=c^6

[(x-b)^1/3]^3=(c^6)^3

x-b=c^18

E
x=c^18+b
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Re: If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   11 Oct 2019, 23:50
Bunuel wrote:
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b

\(\sqrt[3]{x - b} = c^6\)

Or, \(x - b = c^{18}\)

Or, \(x = c^{18} + b\), Answer must be (E)
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siddharthkapoor
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If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   12 Oct 2019, 03:24
Bunuel wrote:
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b


On cubing both the sides of the equation we get,
x-b= \(c^{18}\)
=> x=\(c^{18}\) +b

Therefore, the answer is option E.
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Abhishek009
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Re: If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   13 Mar 2023, 10:44
Bunuel wrote:
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?

A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
\(\sqrt[3]{x - b} = c^6\)

\(x - b = c^{18}\)

Or, \(b = c^{18} - b\), Answer must be (E)
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Re: If (x - b)^(1/3) = c^6, then x = ? [#permalink] New post   31 Mar 2024, 00:45
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Re: If (x - b)^(1/3) = c^6, then x = ? [#permalink]
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