GMATinsight
If x is a positive integer, find the value of x?
1) sum of x consecutive integers is x
2) Product of x consecutive integers is x
Source: http://www.GMATinsight.com Statement 11) sum of x consecutive integers is xThe smallest number in the set = a
\(a + a+1 + a+2 + ... a + (x-1) = x\)
\(ax +\frac{ x(x-1)}{2} = x\)
\(\frac{2ax + x(x-1)}{2} = x\)
As x is positive, we can divide both sides by x
\(\frac{2a + (x-1)}{2} = 1\)
\(2a + x - 1 = 2\)
\(2a + x = 3\)
As a and x are positive numbers, the equation holds true x = 2 and a = 1
We have a definite value of x. Hence, the statement alone is sufficient.
Statement 2 2) Product of x consecutive integers is xAs x represents the number of consecutive integers, x the minimum value of x should be two.
\(a * (a+1) * (a+2) .. * (a + x-1) = x\)
The only value of x that's possible is 2 and the product is
\(1 * 2 = 2\)
IMO D