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IMO B

To check if x < 10 Given: x is an integer

Stmt 1: 7x < 77 or x < 11; x can be 10 (false) or 9,8 .. (Yes) INSUFFICIENT

Stmt 2:190 − 20x < 10 or x > 9 since x is integer, x =10 or 1 or 12 .... so FALSE; SUFFICIENT
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x= int
x<10?

Statement 1 : 7x < 77
7x- 77<0
7(x-11)<0
x<11
Not Sufficient

Statement 2: 190 - 2x < 10
-2x + 190-10<0
-2x + 180 <0
2x - 180 >0
2(x-90)>0
x>90
Sufficient.

Answer :B
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Explanation:
Given: X is an integer, Find: is x<10?
Statement 1 : 7x < 77
x<11
Not Sufficient

Statement 2: 190 - 20x < 10
190-10-20x <0
180 - 20x <0
20(9-x) <0
9<x
Sufficient

IMO-B
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Bunuel
If x is an integer, is x < 10?

(1) 7x < 77
(2) 190 − 20x < 10

Solution


Step 1: Analyse Question Stem


    • x is an integer.
    • We need to find if \(x < 10\).

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE


Statement 1: \(7x < 77\)
    • We have, \(7x < 77\)
    • Dividing both sides of the above inequality by 7, we get,
      o \(x < 11\)
      o So, x can be 10 in that case x = 10 or x can be 9, 8, 7, 6, etc. in that case x < 10
    • So, x can be either equal to 10 or it can be less than 10.
      o We are getting contradictory results.
Hence, statement 1 is NOT sufficient and we can eliminate answer Options A and D.

Statement 2: \(190 – 20x < 10\)
    • We have, \(190 – 20x < 10\)
    • Dividing both sides of the above inequality by 10, we get,
      o \(19 – 2x < 1\)
    • Subtracting 19 from both sides of the above inequality, we get,
      o \(-2x < -18\)
    • Dividing both sides of the above inequality by -2, we get,
      o \(x > 9\)
      o So, x can be 10 in that case x = 10 or x can be 11, 12, 13, 14, etc. in that case x >10
    • So, x can be either equal to or greater than 10, but x can not be less than 10.
Hence, statement 2 is sufficient.

Thus, the correct answer is Option B.
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IMO B

Statement 1 : 7x < 77
x<11
Not Sufficient

Statement 2: 190 - 20x < 10
190-10-20x <0
180 - 20x <0
20(9-x) <0
9<x

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Bunuel
If x is an integer, is x < 10?

(1) 7x < 77
(2) 190 − 20x < 10


Statement 1: 7x < 77
=> x < 11.
=> x could be 10 or less than 10.
Insufficient.

Statement 2: 190 − 20x < 10
=> 180 < 20x
=> x> 9
=> x could again be 10 or more.
=> x is not less than 10.
Thus Sufficient.

Answer is B.
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