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GMATinsight
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If x # y = 3x^2 – y and x @ y = x + 2y, which of the following is equal to 2x # (2x @ y)?

A. 2x^2 + 8xy + 4y^2
B. -x^2 + 8x – 4y
C. 10x^2 – 8 – 4y
D. 8x^2 – 4y^2
E. 12x^2 – 2x – 2y

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Given : x # y = 3x^2 – y and x @ y = x + 2y,

Such questions can very well be solved with some substitution of value

Let, @x=1 and y=1
2x @ y = 2 1 = 2 + 2*1 = 4

Question stem has value, 2x # (2x @ y) = 2*1 # (4) = 2 # 4 = 2*2^2 - 4 = 8 - 4 = 4


Options @x=1 and y=1

A. 2x^2 + 8xy + 4y^2 = 2 + 8 + 4 = 14 i.e. not equal to 4 INCORRECT OPTION
B. -x^2 + 8x – 4y = -1 + 8 - 4 = 3 i.e. not equal to 4 INCORRECT OPTION
C. 10x^2 – 8 – 4y = 10 - 8 - 4 = -2 i.e. not equal to 4 INCORRECT OPTION
D. 8x^2 – 4y^2 = 8 - 4 = 4 CORRECT OPTION
E. 12x^2 – 2x – 2y = 12 - 2 - 2 = 8 i.e. not equal to 4 INCORRECT OPTION

Answer: Option D

Interesting approach.

GMATinsight, I think you have mentioned incorrectly that 2*1 # (4) = 2 # 4 = 2*2^2 - 4 = 8 - 4 = 4 ---> It should be 2*1 # (4) = 2 # 4 = 3*2^2 - 4 = 12 - 4 = 8 with E as the correct answer. Given : x # y = 3x^2 – y and not x # y = 2x^2 – y
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2x#(2x@y)
= 3(2x)^2 - (2x@y)
= 12x^2 - (2x+2y)= 12x^2 -2x-2y
Option E
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Bunuel
If x # y = 3x^2 – y and x @ y = x + 2y, which of the following is equal to 2x # (2x @ y)?

A. 2x^2 + 8xy + 4y^2
B. -x^2 + 8x – 4y
C. 10x^2 – 8 – 4y
D. 8x^2 – 4y^2
E. 12x^2 – 2x – 2y

Kudos for a correct solution.

2x @ y = 2x + 2y
2x # (2x @ y) = 2x # (2x + 2y) => 3(2x)^2 - (2x + 2y) => 12x^2 - 2x - 2y.

Option E.
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Bunuel
If x # y = 3x^2 – y and x @ y = x + 2y, which of the following is equal to 2x # (2x @ y)?

A. 2x^2 + 8xy + 4y^2
B. -x^2 + 8x – 4y
C. 10x^2 – 8 – 4y
D. 8x^2 – 4y^2
E. 12x^2 – 2x – 2y

Kudos for a correct solution.

800score Official Solution:

Recall from the rules of order of operations (PEMDAS), that we always work with what is in parenthesis first. Essentially, we want to work from the inside out with this problem.

2x # (2x @ y) = 2x # (2x + 2y) = 3(2x)^2 – (2x + 2y) = 12x^2 – 2x – 2y.

The correct answer is E.
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2x @ y = 2x + 2y
2x # (2x @ y) = 2x # (2x + 2y) =------> 3(2x)^2 - (2x + 2y) =-----> 12x^2 - 2x - 2y

Hence E.
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