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If xy ≠ 0, is 1/x +1/y = 16?

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If xy ≠ 0, is 1/x +1/y = 16? [#permalink]

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If xy ≠ 0, is 1/x +1/y = 16?

(1) x + y = 16xy

(2) x = y
[Reveal] Spoiler: OA
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Re: If xy ≠ 0, is 1/x +1/y = 16? [#permalink]

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New post 23 Nov 2014, 04:54
If xy ≠ 0, is 1/x +1/y = 16?

(1) x + y = 16xy --> divide by xy: x/(xy) + y/(xy) = 16 --> 1/y + 1/x = 16. Sufficient.

(2) x = y --> the question becomes whether 1/x + 1/x = 16 or whether x = 1/8. We cannot answer this, thus the statement is not sufficient.

Answer: A.

Hope it's clear.
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Re: If xy ≠ 0, is 1/x +1/y = 16? [#permalink]

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New post 23 Nov 2014, 23:47
Given xy ≠ 0,
Solving this equation further 1/x +1/y = 16
(x+y)/xy=16...............A

1) x+y=16xy;
Inserting the value for x+y in equation A equates the both sides.SUFFICIENT.

2)x=y;
This will give any definite result for the equation A.
L.H.S ≠R.H.S INSUFFICIENT


Answer A
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Re: If xy ≠ 0, is 1/x +1/y = 16? [#permalink]

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New post 09 Aug 2017, 21:08
blingbling wrote:
If xy ≠ 0, is 1/x +1/y = 16?

(1) x + y = 16xy

(2) x = y


(1) \(x + y = 16xy\)

\(\frac{x+ y}{xy} = 16\)

\(\frac{x}{xy} + \frac{y}{xy} = 16\)

\(\frac{1}{x} + \frac{1}{y} = 16\)

Hence I is Sufficient.

(2) \(x = y\)

We do not have value of either \(x\) or \(y\), hence we cannot find if \(\frac{1}{x} + \frac{1}{y} = 16\)

Hence II is Not Sufficient.

Answer (A)...
Re: If xy ≠ 0, is 1/x +1/y = 16?   [#permalink] 09 Aug 2017, 21:08
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