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19 Sep 2017, 01:30
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If xy = 4, what is the value of xy(x – y) ?
(1) x^2*y = 16
(2) x + y = 5
(1) x^2*y = 16
(2) x + y = 5
19 Sep 2017, 02:09
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A
Substitute xy value in x^2*y=16. It will give us x=4&y=1
B doesn't give any specific values.
So option A
Sent from my iPhone using GMAT Club Forum
Substitute xy value in x^2*y=16. It will give us x=4&y=1
B doesn't give any specific values.
So option A
Sent from my iPhone using GMAT Club Forum
19 Sep 2017, 02:27
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If xy = 4
Find: xy(x – y)
(1) x^2*y = 16
=> x * xy = 16 => x=4
=> as xy=4 => y =1
so xy(x-y) = 4(4-1) = 4*3 = 12
Sufficient
(2) x + y = 5
xy=4 => \(x=\frac{4}{y}\)
\(\frac{4}{y}+ y= 16\) => \(y^2-5y+4 = 0\) => y=1 or 4
as xy=4 => x=4 or 1.
As we have 2 values of x and y we get 2 values for xy(x – y)
Insufficient
Answer: A
Find: xy(x – y)
(1) x^2*y = 16
=> x * xy = 16 => x=4
=> as xy=4 => y =1
so xy(x-y) = 4(4-1) = 4*3 = 12
Sufficient
(2) x + y = 5
xy=4 => \(x=\frac{4}{y}\)
\(\frac{4}{y}+ y= 16\) => \(y^2-5y+4 = 0\) => y=1 or 4
as xy=4 => x=4 or 1.
As we have 2 values of x and y we get 2 values for xy(x – y)
Insufficient
Answer: A
