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Re: If xy < zy < 0, is y positive? 1. x < z 2. x is negative
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08 Jan 2016, 23:48
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shasadou wrote:
If xy < zy < 0, is y positive?
(1) x < z (2) x is negative
xy < zy < 0 Both xy and zy are negative. Either y is negative, x and z both are positive and x > z. Or y is positive, x and z both are negative and x < z.
Question: Is y positive?
(1) x < z If x < z, x and z are both negative and y is positive. Sufficient.
(2) x is negative If x is negative, z is also negative and then y must be positive. Sufficient.
Answer (D)
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Re: If xy < zy < 0, is y positive? 1. x < z 2. x is negative
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10 Jan 2016, 19:13
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
If xy < zy < 0, is y positive?
(1) x < z (2) x is negative
When you modify the original condition and the question, it becomes (x-z)y<0에서 y>0? --> x-z<0?. x<Z에서 1) is yes, which is sufficient. For 2), if x<0, y>0 derived from xy<0, which is yes and sufficient. Therefore, the answer is D.
Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
_________________
If xy < zy < 0, is y positive? 1. x < z 2. x is negative
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23 Jul 2018, 11:44
KarishmaB wrote:
shasadou wrote:
If xy < zy < 0, is y positive?
(1) x < z (2) x is negative
xy < zy < 0 Both xy and zy are negative. Either y is negative, x and z both are positive and x > z. Or y is positive, x and z both are negative and x < z.
Question: Is y positive?
(1) x < z If x < z, x and z are both negative and y is positive. Sufficient.
(2) x is negative If x is negative, z is also negative and then y must be positive. Sufficient.
Answer (D)
as per the question, it asks y(x-z)<0; I agree for option 1 is sufficient on the basis that x<z; for the second option, since x is -ve x=-5 and z=-4 then y(-5-(-4))<0; hence y is +ve x=-5 and z=-10 then y(-5-(-10))<0; here y should be -ve
there are conflicting solutions whether y is +ve/-ve
Re: If xy < zy < 0, is y positive? 1. x < z 2. x is negative
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23 Jul 2018, 11:54
harish1986 wrote:
KarishmaB wrote:
shasadou wrote:
If xy < zy < 0, is y positive?
(1) x < z (2) x is negative
xy < zy < 0 Both xy and zy are negative. Either y is negative, x and z both are positive and x > z. Or y is positive, x and z both are negative and x < z.
Question: Is y positive?
(1) x < z If x < z, x and z are both negative and y is positive. Sufficient.
(2) x is negative If x is negative, z is also negative and then y must be positive. Sufficient.
Answer (D)
as per the question, it asks y(x-z)<0; I agree for option 1 is sufficient on the basis that x<z; for the second option, since x is -ve x=-5 and z=-4 then y(-5-(-4))<0; hence y is +ve x=-5 and z=-10 then y(-5-(-10))<0; here y should be -ve
there are conflicting solutions whether y is +ve/-ve
where am I wrong??
From Statement 2, we don't get any information for z & we are not bothered about z, all we need to figure out is whether y > 0
We know from question prompt that xy < 0, hence if x < 0, then y > 0
Re: If xy < zy < 0, is y positive? 1. x < z 2. x is negative
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23 Jul 2018, 11:56
harish1986 wrote:
KarishmaB wrote:
shasadou wrote:
If xy < zy < 0, is y positive?
(1) x < z (2) x is negative
xy < zy < 0 Both xy and zy are negative. Either y is negative, x and z both are positive and x > z. Or y is positive, x and z both are negative and x < z.
Question: Is y positive?
(1) x < z If x < z, x and z are both negative and y is positive. Sufficient.
(2) x is negative If x is negative, z is also negative and then y must be positive. Sufficient.
Answer (D)
as per the question, it asks y(x-z)<0; I agree for option 1 is sufficient on the basis that x<z; for the second option, since x is -ve x=-5 and z=-4 then y(-5-(-4))<0; hence y is +ve x=-5 and z=-10 then y(-5-(-10))<0; here y should be -ve
there are conflicting solutions whether y is +ve/-ve
where am I wrong??
The #'s plugged in are not correct x < z, hence x=-5 and z=-10 is not valid
_________________
Re: If xy < zy < 0, is y positive? 1. x < z 2. x is negative
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20 Feb 2019, 09:47
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Top Contributor
shasadou wrote:
If xy < zy < 0, is y positive?
(1) x < z (2) x is negative
Target question:Is y positive?
Given: xy < zy < 0, Let's focus on this part of the inequality: xy < zy Subtract xy from both sides to get: 0 < zy - xy Factor out the y to get: 0 < y(z - x) (this will come in handy later)
Statement 1: x < z Subtract x from both sides to get: 0 < z - x In other words, (z - x) is POSITIVE This means we can take our given inequality 0 < y(z - x) and divide both sides by (z - x) to get: 0 < y So, the answer to the target question is YES, y IS positive Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: x is negative The given information tells us that xy < zy < 0 This means xy < 0 In other words, xy is NEGATIVE So, if x is negative, then it MUST be the case that y is POSITIVE Since we can answer the target question with certainty, statement 2 is SUFFICIENT
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53% (01:30) correct 
