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If y and z are positive integers such that y2z=123.24, the remainder

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If y and z are positive integers such that y2z=123.24, the remainder  [#permalink]

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New post Updated on: 04 May 2019, 10:01
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Difficulty:

  75% (hard)

Question Stats:

51% (02:00) correct 49% (01:59) wrong based on 89 sessions

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If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined

Originally posted by kiran120680 on 04 May 2019, 08:57.
Last edited by kiran120680 on 04 May 2019, 10:01, edited 1 time in total.
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Re: If y and z are positive integers such that y2z=123.24, the remainder  [#permalink]

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New post 04 May 2019, 09:31
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Y and x are integers so the multiplication can not be in decimal


Can you check if there is any typo ....

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Re: If y and z are positive integers such that y2z=123.24, the remainder  [#permalink]

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New post 04 May 2019, 23:28
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If y/2z = 123.24 then y/z =246.48
That implies z*0.48 is the remainder which is 0.52 times lesser of z

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Re: If y and z are positive integers such that y2z=123.24, the remainder  [#permalink]

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New post 25 May 2019, 06:16
kiran120680 wrote:
If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined


Kudos for a better explanation.
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Re: If y and z are positive integers such that y2z=123.24, the remainder  [#permalink]

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New post 25 May 2019, 06:25
1
kiran120680 wrote:
If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined


Good sum,

Concept
X = yQ + R
x when divided by y gives a quotient Q and remainder R such that 0<=R<y

y/z = 246.48

y= 246*z + z(.48)
Remainder= .48z

Answer= { z(1-.48)/z }*100 = 52% C
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Re: If y and z are positive integers such that y2z=123.24, the remainder  [#permalink]

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New post 25 May 2019, 08:20
LeoN88 wrote:
kiran120680 wrote:
If y and z are positive integers such that y/2z=123.24, the remainder obtained when y is divided by z is what percentage lesser than z?


A. 24%
B. 48%
C. 52%
D. 76%
E. Cannot be Determined


Good sum,

Concept
X = yQ + R
x when divided by y gives a quotient Q and remainder R such that 0<=R<y

y/z = 246.48

y= 246*z + z(.48)
Remainder= .48z

Answer= { z(1-.48)/z }*100 = 52% C


Thanks for explanation :thumbup:
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Re: If y and z are positive integers such that y2z=123.24, the remainder   [#permalink] 25 May 2019, 08:20
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If y and z are positive integers such that y2z=123.24, the remainder

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