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Bunuel
ax + b = cx + d
x(a-c)=d-b
x=(d-b)/ (a-c)

if a=c then x becomes undefined, thats why I chose A.
whats wrong here?
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Bunuel
ax + b = cx + d
x(a-c)=d-b
x=(d-b)/ (a-c)
if a=c then x becomes undefined, thats why I chose A.
whats wrong here?

If a=c, then we cannot write the highlighted part but x*0 = d-b would still be perfectly valid equation, which would mean that d-b=0 and x can take any value.
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If y = ax + b and y = cx + d for all values of x, where a, b, c, and d are constants, then all the following must be true EXCEPT:

A. a = c

B. ac = -1

C. a^2 = c^2

D. \(|a| = \sqrt{c^2}\)

E. ac + 1 > 0

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a=b; because both are coefficients of x.
assuming a = 1
Eliminate option a, because it is true. If option a is eliminated, then you must also eliminate option c; AV and Root both suggest +/- relationship; therefore the absolute value of a = c; eliminate d. Option E is eliminate because it can be true.

Option B suggests either a or b is a negative, but not both. Since a = b, therefore, B, ac = -1 cannot be true.
Answer is B
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OA: B
y = ax + b and y = cx + d for all values of x, means that both lines are coincident.
So option that will imply that they are not coincident, will be the answer.
Product of slope of two non vertical perpendicular line is -1.
i.e if m1.m2=-1; then line y=m1x+C1 and line y=m2x+C2 will be perpendicular.
Option B : ac =-1 means that line y = ax + b and y = cx + d are perpendicular.
So it must not be not true.
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if a=10, x=3 and b=3
y=ax+b............33=(10*3)+3

if c=11, x=3, and d=0
y=cx+d............33=11*3+0

then a is not qual to c and b is not qual to d. (option a, option b both are correct) @bunnel
could u pls guide
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Another reason for B.
product of the slope of 2 lines are -1 if they are perpendicular to each other. I dont think the lines can be equal if they are perpendicular.
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