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If y is a positive integer, and |x| < 5 − y, then what is the least possible value of x?
A. 4 B. 1 C. 0 D. -1 E. -4
*This is from a retired post and I am posting it again for a clear explanation*
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I really don't understand the logic behind OA as C unless what you are looking for is least possible value of |x| and not x. Even the retired thread gives answer as C..
Now |x|<5-y, where y is a positive integer... 5-y will always be non-negative as we have |x| on other side.. But |x| can give x as both positive and negative, and is NOT given as an integer
For least possible value, we will take the max value of 5-y which is 5-1=4.. Now |x|<4, so possible value of x is 3.99, 3, 2, 1, 0.5, 1, -1, -2 , -3, -3.999.. Least value is -3.9999999..
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