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605-655 Level|   Graphs|   Math Related|      
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danzig
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In 2010, there were four used-car dealers in City Z. The graphic shows Updated on: 26 Oct 2023, 12:38
Originally posted by danzig on 08 Feb 2013, 11:44.
Last edited by Sajjad1994 on 26 Oct 2023, 12:38, edited 4 times in total.
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Dropdown 1: More than Dropdown 2: 46
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69% (02:26) correct 31% (02:31) wrong based on 994 sessions

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In 2010, there were four used-car dealers in City Z. The graphic shows the monthly sales data for 2010 for two of those dealers as well as the citywide average for used-car dealers for those months.

Based on the given information, use the drop-down menus to most accurately complete the following statements.

1. ABC Cars and XYZ Automotive accounted for half of all used-car sales in City Z for 2010.

2. In June 2010, the two used-car dealers that are not specified by the graphic sold a total of exactly cars.

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Dropdown 1: More than Dropdown 2: 46
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In 2010, there were four used-car dealers in City Z. The graphic shows 09 Feb 2013, 02:29
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danzig
Please, explain the answer of question 30A (below). The OE of the OG is not good at all. In summary, they say this:
"Both ABC and XYZ sales were at or above the citywide average for every single month in 2010. Thus their combined sales must have been greater than the combined sales of the two dealers not included in the graph. Therefore ABC Cars and XYZ Automotive must have accounted for more than half of all used-car sales in City Z in 2010."
Please, provide a more detailed explanation.

Also, what would have happened if the total number of dealers (not only in the graph) had been 20? The answer would have not been the same, right? That's why I believe that the OE is not sufficient to explain the answer. Please your help.
Thanks!

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Actually, the OE is fine.

Take a simpler view:

Average of 4 numbers is 15. (Total sum of all four numbers will be 60.)
Two of the numbers are 20 and 22. Both the numbers are more than the average.
What can you say about the other two numbers? Can you say that they together will account for less than half of total sum? Yes, you can. Since the contribution of the given two numbers is more than half of the total sum, the contribution of the other two numbers will be less than half of the total sum.

Similarly, in this question you have 4 car dealers (given in the question). The total number of car dealers cannot be 20 since you are given that the total number is 4.
Two of them account for more than half of the total sales almost every month (since they lie either above or at average). Hence, for 2010, the two of them will account for more than half of all sales.
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In 2010, there were four used-car dealers in City Z. The graphic shows 11 Feb 2013, 11:45
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VeritasPrepKarishma


Actually, the OE is fine.

Take a simpler view:

Average of 4 numbers is 15. (Total sum of all four numbers will be 60.)
Two of the numbers are 20 and 22. Both the numbers are more than the average.
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Sorry, but I didnt get where from u got numbers 15 ,20 and 22
could u please elaborate a bit more?
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In 2010, there were four used-car dealers in City Z. The graphic shows 11 Feb 2013, 20:05
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VeritasPrepKarishma


Actually, the OE is fine.

Take a simpler view:

Average of 4 numbers is 15. (Total sum of all four numbers will be 60.)
Two of the numbers are 20 and 22. Both the numbers are more than the average.
Sorry, but I didnt get where from u got numbers 15 ,20 and 22
could u please elaborate a bit more?
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The numbers are just an example.
If average of 4 numbers is 15, the total sum of the numbers will be 15*4 = 60
If two of the numbers are 20 and 22 (both more than the average), then their sum is more than half the total sum (because half of the numbers are more than the average) i.e. the sum of these two numbers will be more than 30.
The other two numbers will add up to be less than half the total sum i.e. the other two numbers will add up to be less than 30.

This question tests the same concept.
The white squares are the average. In almost all months, the black squares and the white circles are above the average i.e. sales of ABC and XYZ are above the average. So they will sum up to be more than half the total sum.
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In 2010, there were four used-car dealers in City Z. The graphic shows 10 Sep 2021, 12:45
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Official Explanation

1. ABC Cars and XYZ Automotive accounted for_______half of all used-car sales in City Z for 2010.

Since the white circles (connected by blue lines) and the filled squares (connected by black lines) in the graph are consistently at or above the empty squares (connected by dotted lines), it follows that both ABC Cars and XYZ Automotive were at or above the citywide average for every single month in 2010. Thus their combined sales must have been greater than the combined sales of the two dealers not included in the graph. Therefore ABC Cars and XYZ Automotive must have accounted for more than half of all used-car sales in City Z in 2010.

The correct answer is more than.

2. In June 2010, the two used-car dealers that are not specified by the graphic sold a total of exactly______________cars.

In June 2010, the citywide average was 26 cars. This means that the four dealers sold a combined 4(26) = 104 cars. Of those 104 cars, ABC Cars sold 30 and XYZ Automotive sold 28. This implies that the other two dealers sold 104 − 30 − 28 = 46 cars.

The correct answer is 46.
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In 2010, there were four used-car dealers in City Z. The graphic shows 29 May 2025, 17:51
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